Isotonic, hypertonic and hypotonic cells: describe

Chemistry

1 answer:

olya-2409 [2.1K]3 years ago

5 0

<h3>♫ :::::::::::::::::::::::::::::: // Hello There ! // :::::::::::::::::::::::::::::: ♫</h3>

➷ An isotonic cell has the same concentration inside the cell as the outside solution. This would mean there is no net movement of water. Isotonic cells are sometimes called 'normal'

Hypertonic cells have a higher water concentration inside the cell than outside the cell. This causes water to move out of the cell and make the cell shrivel.

Hypotonic cells are the opposite of hypertonic cells. They have a lower water concentration inside the cell than outside. This causes water to move into the cell and make the cell bloat.

[Any further queries, feel free to ask]

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

You might be interested in

Which power source uses the earth’s internal heat?

Nataly_w [17]

Answer:

Its geothermal energy.

Explanation:

hope this helps

5 0

3 years ago

Determine total H for bonds broken and formed, the overall change in H, and the final answer with units. Is it ENDOthermic or EX

Mrac [35]

E(Bonds broken) = 1371 kJ/mol reaction
E(Bonds formed) = 1852 kJ/mol reaction

ΔH = -481 kJ/mol.
The reaction is exothermic.

<h3>Explanation</h3>

2 H-H + O=O → 2 H-O-H

There are two moles of H-H bonds and one mole of O=O bonds in one mole of reactants. All of them will break in the reaction. That will absorb

E(Bonds broken) = 2 × 436 + 499 = 1371 kJ/mol reaction.
ΔH(Breaking bonds) = +1371 kJ/mol

Each mole of the reaction will form two moles of water molecules. Each mole of H₂O molecules have two moles O-H bonds. Two moles of the molecule will have four moles of O-H bonds. Forming all those bond will release

E(Bonds formed) = 2 × 2 × 463 = 1852 kJ/mol reaction.
ΔH(Forming bonds) = - 1852 kJ/mol

Heat of the reaction:

$\Delta H_{\text{rxn}} = \Delta H(\text{Breaking bonds}) + \Delta H(\text{Forming bonds})\\\phantom{ \Delta H_{\text{rxn}}} = +1371 + (-1852) \\\phantom{ \Delta H_{\text{rxn}}} = -481 \; \text{kJ} / \text{mol}$