What is 5)47 and the remander

Mathematics

2 answers:

adoni [48]3 years ago

7 0

Divide 47 by 5
47/5
5 only goes into 47 9 times and the remainder would be 2
9 the remainder would be 2

Vesna [10]3 years ago

4 0

9, remainder= 2
You can double check this by doing 9 times 5=45
Then add 2(remainder)

You might be interested in

Amare worked twice as many hours as jing they worked a total of 42 hours help how xo i do this

LenaWriter [7]

Amare=x Jing=Y x=2y 42=x+Y (<-These are 2 base equations for systems of equations) 42=2y + Y 42=3y (Y=14) 42=x + 14 42-14=x (x=28) Amare=28 Jing=14

5 0

3 years ago

A certain transverse wave is described by y(x,t)=bcos[2π(xl−tτ)], where b = 5.90 mm , l = 29.0 cm , and τ = 3.90×10−2 s .

Vitek1552 [10]

Part A:

The general form of the equation of a transverse wave is given by:

$y(x,t)=A\cos\left[2\pi\left( \frac{x}{\lambda} - \frac{t}{T} \right)\right]$

where A is the amplitude, $\lambda$ is the wavelength, and T is the period.

Given that a certain transverse wave is described by:

$y(x,t)=bcos[2\pi(xl-t\tau)]$ , where b = 5.90 mm , l = 29.0 cm , and \tau = 3.90\times10^{-2} s

Thus, the amplitude is b = 5.90 mm = 5.9\times10^{-3} \ m

Part B:

The general form of the equation of a transverse wave is given by:

$y(x,t)=A\cos\left[2\pi\left( \frac{x}{\lambda} - \frac{t}{T} \right)\right]$

where A is the amplitude, $\lambda$ is the wavelength, and T is the period.

Given that a certain transverse wave is described by:

$y(x,t)=bcos[2\pi\left(\frac{x}{l}-\frac{t}{tau}\right)\right]$ , where b = 5.90 mm , l = 29.0 cm , and \tau = 3.90\times10^{-2} s

Thus,

$y(x,t)=bcos[2\pi\left(\frac{x}{l}-\frac{t}{tau}\right)\right\\ \\ \frac{1}{\lambda} = \frac{1}{l} \\ \\ \Rightarrow\lambda= l =28.0 \ cm=\bold{2.8\times10^{-1}}$

Part C:

The general form of the equation of a transverse wave is given by:

$y(x,t)=A\cos\left[2\pi\left( \frac{x}{\lambda} - \frac{t}{T} \right)\right]$

where A is the amplitude, $\lambda$ is the wavelength, and T is the period.

Given that a certain transverse wave is described by:

$y(x,t)=bcos[2\pi\left(\frac{x}{l}-\frac{t}{tau}\right)\right]$ , where b = 5.90 mm , l = 29.0 cm , and \tau = 3.90\times10^{-2} s

The wave's frequency, f, is given by:

 $f= \frac{1}{T} = \frac{1}{\tau} = \frac{1}{3.40\times10^{-2}} =\bold{29.4 \ Hz}$

Part D:

Given that the the wavelength is $2.8\times10^{-1} \ m$ and that the wave's frequency is 29.4 Hz

The wave's speed of propagation, v, is given by:

$v=f\lambda=29.4(2.8\times10^{-1})=8.232 \ m/s$

4 0

3 years ago

Tan 56 degree=24/x. Find the value of x to the nearest tenth

Fiesta28 [93]

Solve for x, simplify the left hand side.
x= 24/tan(56)
=24/1.48=16.2

8 0

3 years ago

The length of time it takes to find a parking space at 9

OlgaM077 [116]

Under a normal distribution curve, if 70% of the people fall to the right of the observation point, then 30% of the people would fall to the left of the observation point. Note, the observation point is the number we are looking for in this instance(how long it takes to find a parking space).

We'll need to use a z table and the formula for a z score to find what we are looking for. First, convert 30% to 0.30 and refer to a standard z table that represents the area under a normal curve to the left of specific z scores. We'll need to look in the body of the table and find the closest decimal value compared to our 0.30. Once you find this decimal number, reference the row and column values to obtain the z score. Looks like this will be -0.53.

Now we can use the z score formula to find our observation point:
z score = (x - Mean)/standard deviation, where x represents the observation point we're looking for!

Substituting into the formula we have: $-0,53 = \frac{x-4}{2}$
Solving this equation for x, we find x = 2.94

This represents our observation point and we can assume that 70% of people take more than 2.94 minutes to find a parking space.

8 0

4 years ago

Is d = 11 a solution to the inequality below? d<2 Yes or no

zepelin [54]

Answer:

the answer is false 11 is greater than 2 so no the answer is no

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers