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LenaWriter [7]
3 years ago
15

Translate into an algebraic expression 40 increased by x%

Mathematics
1 answer:
marin [14]3 years ago
6 0

Answer:

x+2/5x

Step-by-step explanation:

x%of 40 is 2/5x

...40 increased by x% of it self = x+2/5x

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Indicate in standard form the equation of the line passing through the given point and having the given slope
Naddik [55]
ANSWER


The equation is

y - 5x + 20 = 0


EXPLANATION

Let the equation be
y = mx + c

where
m = 5
is the slope of the line.


We substitute this value to obtain,

y = 5x + c


Since the line passes through
(4,0)
we can use this point to determine the value of c.



We substitute this point to obtain,

0 = 5(4) + c


0 = 20 + c


c =  - 20


Our equation now becomes

y = 5x - 20


We can write this in standard form as


y - 5x + 20 = 0
6 0
3 years ago
A chicken weighs t lbs. It needs to be cooked for 20 minutes per lb plus an extra 15 minutes. What is the total cooking time? Is
Nostrana [21]

Answer:

Total cooking time = 20t + 15

The expression 15t + 20 is wrong.

Step-by-step explanation:

weight of chicken = t lbs

cook time per lb = 20 minutes

This means that:

1 lb weight requires a cooking time of 20 minutes

1 lb = 20 minutes

∴ t lbs = 20 × t = 20t minutes.

We were also told that each chicken required an extra cooking time of 15 minutes, in addition to the total cooking time due to the weight. Therefore, the total cooking time is calculated thus:

Total cooking time = cooking time due to weight + 15 minutes

Total cooking time = 20t + 15

Hence the expression 15t + 20 is wrong, due to the explanation given above.

8 0
3 years ago
Gabrielle and John each
vivado [14]

Answer:

64=2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2=2^6

Step-by-step explanation:

Gabrielle and John each

wrote the prime factorization of 64.

64 can be break into 32 times 2

32 can be break into 16 times 2

16 can be break into 8 and 2

8 can be break into 4 times 2

4 can be break into 2 times 2

So 64 is equal to 2 times 2 times 2 times 2 times 2 times 2

64=2^6

7 0
3 years ago
A bag has 4 green marbles, 3 red marbles, and 3 yellow marbles. What is the probability that you pick
STALIN [3.7K]

|\Omega|=10\cdot9=90\\ |A|=3\cdot3=9\\\\ P(A)=\dfrac{9}{90}=\dfrac{1}{10}=10\%

6 0
3 years ago
Read 2 more answers
Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
3 years ago
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