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lbvjy [14]
3 years ago
13

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5?

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0
- 3 x² - 4 x + 5 = 0
x_{1} = \frac{4+ \sqrt{16+60} }{-6} =  \frac{4+8.718}{-6}
x1 = -2.12
x_{2} = \frac{4-8.718}{-6}
x2= 0.786

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Which statements about the system are true? Check all that apply. y =1/3 x – 4 3y – x = –7 The system has one solution. The syst
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Answer:

The true statements are:

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Step-by-step explanation:

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- The equations are ax+ by = c , dx + ey = f

# If the two lines parallel to each other, then there is no solution

- The equations are ax+ by = c , ax + by = d in its simplest form ,

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  c , d are the numerical terms

# If the two lines coincide (over each other), then there are infinite

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  a is the coefficient of x , b is the coefficient of y and c is the

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* Lets solve the problem

∵ The system of equation is:

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∴ 3y - x = -12

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A

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