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lbvjy [14]
3 years ago
13

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5?

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0
- 3 x² - 4 x + 5 = 0
x_{1} = \frac{4+ \sqrt{16+60} }{-6} =  \frac{4+8.718}{-6}
x1 = -2.12
x_{2} = \frac{4-8.718}{-6}
x2= 0.786

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\textsf{Hey there!}

\textsf{Put these numbers in order from GREATEST to LEAST}

\bullet{\mathsf{ \ 1\dfrac{6}{8}}}

\bullet\mathsf{\ -\dfrac{10}{25}}

\bullet{\mathsf{\ -\dfrac{18}{25}}}

\bullet{\textsf{ 1}}

\star\textsf{ We know that fractions, decimals, negatives are BELOW 0 (on the left} \textsf{of 0)}

\star\textsf{ \& we also know that positives and real numbers is/are ABOVE 0 (to the right} \textsf{of 0)}

\textsf{Now we can answer your question}

\blacksquare \ \mathsf{1\dfrac{6}{8} = \dfrac{14}{8} = 1.75}

\blacksquare\ \mathsf{-\dfrac{10}{25} = -0.40}

\blacksquare\ \mathsf{- \dfrac{18}{25} = -0.72}

\blacksquare \ \mathsf{1 = 1}

\textsf{Look carefully at the stuff converted to the decimal or regular number \& } \textsf{you will  have your answer from \underline{greatest} to \underline{least}}

\boxed{\textsf{If you solved correctly you  SHOULD have: \boxed{\mathsf{\dfrac{14}{8}, \ 1, \ - \dfrac{10}{25}\ ,\  -\dfrac{18}{25}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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