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lbvjy [14]
3 years ago
13

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5?

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0
- 3 x² - 4 x + 5 = 0
x_{1} = \frac{4+ \sqrt{16+60} }{-6} =  \frac{4+8.718}{-6}
x1 = -2.12
x_{2} = \frac{4-8.718}{-6}
x2= 0.786

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