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lbvjy [14]
3 years ago
13

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5?

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0
- 3 x² - 4 x + 5 = 0
x_{1} = \frac{4+ \sqrt{16+60} }{-6} =  \frac{4+8.718}{-6}
x1 = -2.12
x_{2} = \frac{4-8.718}{-6}
x2= 0.786

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Answer:

x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3

Step-by-step explanation:

Let's solve for x.

3x2+y2=9

Step 1: Add -y^2 to both sides.

3x2+y2+−y2=9+−y2

3x2=−y2+9

Step 2: Divide both sides by 3.

3x^2/3= -y^2+9/3

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x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3

Hope it helped!

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3 years ago
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Answer:

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Step-by-step explanation:

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Applying this to the question,

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