Question

At elevated temperatures, methylisonitrile (ch3nc) isomerizes to acetonitrile (ch3cn): ch3nc (g) \rightarrow → ch3cn(g) at the start of an experiment, there are 0.200 mol of reactant and 0 mol of product in the reaction vessel. After 25 min, 0.108 mol of reactant (ch3nc) remain. There are ___________ mol of product (ch3cn) in the reaction vessel.

Answer 1

Answer :  there are 0.092 mol of product (CH3CN) in the reaction vessel

Explanation :

The given reaction is

$CH_{3}NC (g) \rightarrow CH_{3}CN (g)$

Let us set up an ICE table for the above reaction.

The initial moles of product are 0

Let us assume "x" is the change. The change is negative for reactant because moles of reactant decrease whereas it is positive for product

Please refer to attached image.

From the ICE table we have equilibrium moles of CH3NC as 0.200 - x.

But we have been give that, 0.108 moles o CH3NC remains after the reaction is complete.

Therefore we have, $0.200 - x = 0.108$

$x = 0.200 - 0.108$

$x = 0.092 mol$

But x is also the moles of product formed during the reaction.

Therefore, there are 0.092 mol of product (CH3CN) in the reaction vessel