Each sentence describes potential and kinetic energy at various locations on a slide. Complete each statement by selecting the p
2 answers:
The question is incomplete, the complete question is;
Each sentence describes potential and kinetic energy at various locations on a slide. Complete each statement by selecting the position of the object on the slide.
An object at position has all kinetic energy. A B or C
An object at position has all potential energy. A B or C
An object at position has about half potential energy and half kinetic energy. A B or C
Answer:
An object at position C has all kinetic energy.
An object at position A has all potential energy.
An object at position B has about half potential energy and half kinetic energy.
Explanation:
Lets take a good look at the image.
At position A, the object is stationary and we know that the energy possessed by an an object by virtue of its position is known as potential energy. Hence at A, the energy possessed by the body is all potential.
At position B, the total mechanical energy of the object becomes potential energy + kinetic energy as the object is now in motion.
At position C, the object is still in motion and the energy is all kinetic.
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Explanation:
The reaction expression is given as;
2H₂ + O₂
→ 2H₂O
From the balance reaction expression:
2 mole of hydrogen gas combines with 1 mole of oxygen gas on the reactant side;
This produces 2 mole of water on the product side of the expression.
The product is in liquid form.
This reaction is a synthesis reaction because a single product is formed from two reactants.
Answer:
<em>so mass in gram=560grams</em>
Explanation:
number of moles=10moles
molar mass=56grams/moles
mass in gram of Fe=?
as we know that
<em>evaluating the formula</em>
<em>number of moles×molar mass=mass in gram</em>
<em>mass in gram=10moles×56grams/moles</em>
<em>mass in gram=560grams</em>
<em>i hope this will help you :)</em>
The equilibrium constant is 0.0022.
Explanation:
The values given in the problem is
ΔG° = 1.22 ×10⁵ J/mol
T = 2400 K.
R = 8.314 J mol⁻¹ K⁻¹
The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.
The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K
So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.
We get,
So, the equilibrium constant is 0.0022.