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Hunter-Best [27]
3 years ago
6

Brainliest if you are correct!! Find the domain of the graphed function.

Mathematics
2 answers:
Ghella [55]3 years ago
7 0

Answer: A) x is greater than or equal to 0

Step-by-step explanation:

The domain of a function is all of the x values that allow the function to work.  The function starts at 0 and goes on indefinitely, so there is no maximum and 0 is the minimum.

hichkok12 [17]3 years ago
5 0

Answer:

A is correct

Step-by-step explanation:

x must be greater or equal to 0

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How much acetic acid is in a 5-liter container that is marked 80% acetic acid? How
Ksenya-84 [330]

Answer:

1 liter I think?

Step-by-step explanation:

I don't know for sure but I am thinking it is 1 liter

8 0
3 years ago
Given the equation square root of quantity 3x plus 6 end quantity equals 3, solve for x and identify if it is an extraneous solu
Novay_Z [31]

Solution is not extraneous, x=1 is correct answer

Step-by-step explanation:

We need to solve the equation \sqrt{3x+6}=3 and find value of x.

Solving:

\sqrt{3x+6}=3\\Taking\,\,square\,\,on\,\,both\,\,sides\\(\sqrt{3x+6})^2=(3)^2\\3x+6=9\\Simplifying:\\3x=9-6\\3x=3\\x=3/3\\x=1

So. Value of x = 1

Now checking if solution is extraneous or not

Solution is extraneous if value of x doesn't satisfy the given equation.

Checking: putting x=1 in the equation \sqrt{3x+6}=3

\sqrt{3x+6}=3\\\sqrt{3(1)+6}=3\\\sqrt{9}=3\\ 3=3

Since x=1, verifies the given equation so, x=1 is not extraneous solution

Solution is not extraneous, x=1 is correct answer

Keywords: Solving equations and finding extraneous roots

Learn more about Solving equations and finding extraneous roots at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/4046256

#learnwithBrainly

5 0
3 years ago
Find the particular solution to y ' = 4sin(x) given the general solution is y = c - 4cos(x) and the initial condition y of pi ov
Lana71 [14]

The general solutions always have some additive/multiplicative constant, that you must fix in the particular solution.

In order to do so, you need to impose that the particular solution passes through a certain point. In your case, you have

y(x) = c-4\cos(x)

and you want

y\left(\dfrac{\pi}{2}\right) = 2

Put everything together, and you have

y\left(\dfrac{\pi}{2}\right) = c-4\cos\left(\dfrac{\pi}{2}\right) = c = 2

Since the cosine is zero in the chosen point. So, we've fixed the value of the constant, and the particular solution is found:

y(x) = 2-4\cos(x)

4 0
3 years ago
F(x)=5(1+0.25)^x,f(4)<br><br> Please show step by step of how you got the answer
satela [25.4K]

Answer:

f(4) = 12.2

Step-by-step explanation:

we are given that x = 4, plug in 4 into the equation

f(4) = 5(1+0.25)^(4)

f(4) = 5(1.25)^(4)

raise 1.25 to the 4th, which is equal to 2.44

f(4) = 5(2.44)

f(4) = 12.2

4 0
3 years ago
Read 2 more answers
These are the values in Devante’s data set. (2, 94.5), (3, 89), (4,80), (6, 71), (7, 63) Devante determines the equation of a li
Sedbober [7]
We know that

The residual value is the observed value minus the predicted value.

RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE]

where

Predicted value.--> the predicted value given the current regression equation

<span>Observed value. --> The observed value for the dependent variable
</span>
find the residuals value

point 1) <span>(2, 94.5)
</span>yˆ=−6x+105.7 

for x=2
Observed value=94.5
Predicted value=-6*2+105.7-----> 93.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[94.5-93.7]----> 0.8-----> 1
point (2,1)

point 2) <span>(3, 89)
</span>yˆ=−6x+105.7 

for x=3
Observed value=89
Predicted value=-6*3+105.7-----> 87.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[89-87.7]----> 1.3-----> 1
point (3,1)

point 3) <span>(4,80)
</span>yˆ=−6x+105.7 

for x=4
Observed value=80
Predicted value=-6*4+105.7-----> 81.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[80-81.7]----> -1.7-----> -2
point (4,-2)

point 4) <span>(6, 71)
</span>yˆ=−6x+105.7 

for x=6
Observed value=71
Predicted value=-6*6+105.7-----> 69.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[71-69.7]----> 1.3 -----> 1
point (6,1)

point 5) <span>(7, 63)
</span>yˆ=−6x+105.7 

for x=7
Observed value=63
Predicted value=-6*7+105.7-----> 63.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[63-63.7]----> 0.7 -----> 1
point (7,1)

using a graph tool
<span>graph the residual plot for the data set.
the points are
</span>(2,1) (3,1) (4,-2) (6,1) (7,1)

see the attached figure

4 0
4 years ago
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