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7nadin3 [17]
3 years ago
10

3/4 2/3 5/6 5/7 least to greatest

Mathematics
2 answers:
KatRina [158]3 years ago
8 0

Answer:

2/3 < 5/7 < 3/4 < 5/6

Step-by-step explanation:

<u>Method 1</u> : Converting to decimals

2/3 = 0.66

5/7 = 0.71

3/4 = 0.75

5/6 = 0.83

0.66 < 0.71 < 0.75 < 0.83

<u>Method </u>2 : Converting to fractions with same denominators

(2x28) / (3x28) = 56 / 84

(5x12)/(7x12) = 60/84

(3x21)/(4x21) = 63/84

(5x14)/(6x14) = 70/84

56 / 84 < 60/84 < 63/84 < 70/84

Lana71 [14]3 years ago
6 0

Answer:

2/3, 5/7, 3/4, 5/6.

Step-by-step explanation:

Convert each one to a decimal fraction:

3/4 = 0.75

2/3 = 0.666..

5/6 = 0.8333..

5/7 = 0.714

So least to greatest is

2/3, 5/7, 3/4, 5/6.

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6) Double a number is equal to the number decreased by five. Find the number.
Lemur [1.5K]

Answer:

B) -5

Step-by-step explanation:

let the number be x

2x=x-5

take x to the other side

2x-x=-5

×=-5

4 0
2 years ago
Can you show the steps <br> thanks .........
Andrews [41]

Answer:

40 black bears

Step-by-step explanation:

Hope it helps.

5 per sample

8 samples

5 x 8 = 40 black bears

4 0
2 years ago
A car braked with a constant deceleration of 16ft/s2, producing skid marks measuring 200 feet before coming to a stop. How fast
Llana [10]

Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.

Step-by-step explanation:

The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,

a = - 16ft/s^2

While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.

This means that it travelled a distance,

s = 200 feet

We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.

Since the car came to a stop, its final velocity, v = 0

Applying Newton's equation of motion,

v^2 = u^2 + 2as

0 = u^2 - 2 × 16 × 200

u^2 = 6400

u = √6400

u = 80 ft/s

7 0
3 years ago
Find the indicated conditional probability
andrezito [222]

Given:

The two way table.

To find:

The conditional probability of P(Drive to school | Senior).

Solution:

The conditional probability is defined as:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Using this formula, we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{P(\text{Drive to school and senior})}{P(\text{Senior})}                      ...(i)

From the given two way table, we get

Drive to school and senior = 25

Senior = 25+5+5

           = 35

Total = 2+25+3+13+20+2+25+5+5

         = 100

Now,

P(\text{Drive to school and senior})=\dfrac{25}{100}

P(\text{Senior})=\dfrac{35}{100}

Substituting these values in (i), we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{\dfrac{25}{100}}{\dfrac{35}{100}}

P(\text{Drive to school }|\text{ Senior})=\dfrac{25}{35}

P(\text{Drive to school }|\text{ Senior})=0.7142857

P(\text{Drive to school }|\text{ Senior})\approx 0.71

Therefore, the required conditional probability is 0.71.

5 0
3 years ago
Read 2 more answers
A painting is 24 in. Wide by 32in. Long. The width of a postcard reductions of the painting is 3in. How long is the postcard
s344n2d4d5 [400]

Answer:

4 inches.

Step-by-step explanation:

24 32

---- = -----

3 x

Cross multiply.

24x = (32)(3) = 96.

96 / 24 = 4.

Hope this helped and good luck! (:

7 0
3 years ago
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