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nataly862011 [7]
3 years ago
11

Solving Linear Systems by Substitution x+y=5 -3x+2y=5

Mathematics
2 answers:
iris [78.8K]3 years ago
7 0

Answer:

<h2>X=1</h2><h2>y=4</h2>

Please see the attached picture for full solution...

Hope it helps...

Good luck on your assignment...

artcher [175]3 years ago
3 0

Answer:

x=8.5

y=-3.5

Step-by-step explanation:

lets say  x=5-y

substituting x in the other equation gives -3(5-y)+2y=5

-15+3+2y=5

2y=5+15-3

2y=17

y=8.5

from equation 1    : x+8.5=5

x=5-8.5

x=-3.5

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Answer:

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Step-by-step explanation:

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4. One come last, Two comes first, and three comes second.

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A circle is centered on point B. Points A, C and D lie on its circumference.
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Answer:

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mrs peters bought 7 1/2 yards of fabric she needs another 4 7/8 yards how many yards of fabric does she need altogether
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3 years ago
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
Slav-nsk [51]

Answer:

Systolic on right

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

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The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

CV= \frac{\sigma}{\mu}

And the best estimator is \hat {CV} =\frac{s}{\bar x}

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

\bar x = 127.5, s= 18.68

So then the coeffcient of variation is given by:

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

For this case we have the following values:

\bar x = 74.2 s= 12.65

So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

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Is there a answer choice of -5
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