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nataly862011 [7]
3 years ago
11

Solving Linear Systems by Substitution x+y=5 -3x+2y=5

Mathematics
2 answers:
iris [78.8K]3 years ago
7 0

Answer:

<h2>X=1</h2><h2>y=4</h2>

Please see the attached picture for full solution...

Hope it helps...

Good luck on your assignment...

artcher [175]3 years ago
3 0

Answer:

x=8.5

y=-3.5

Step-by-step explanation:

lets say  x=5-y

substituting x in the other equation gives -3(5-y)+2y=5

-15+3+2y=5

2y=5+15-3

2y=17

y=8.5

from equation 1    : x+8.5=5

x=5-8.5

x=-3.5

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Please help lot of points at stake- and will give brainly.
Veronika [31]

Answer:

a)1400 + 300x ≤ 5000

b) x ≤ 12 days

Step-by-step explanation:

a) Since the grocery store owner wants to stay within budget then, this means he would be spending at most $5,000

The word at most is represented by the inequality sign ≤ = Less than or equal to

Let x = Number of days

Hence,

Our inequality equation is

$1400 + 300× x ≤ $5000

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3 0
3 years ago
The polynomial $f(x)$ has degree 3. If $f(-1) = 15$, $f(0)= 0$, $f(1) = -5$, and $f(2) = 12$, then what are the $x$-intercepts o
Alex_Xolod [135]

Your calculator's cubic regression function can tell you the equation is

... f(x) = 2x³ + 5x² -12x = x(x +4)(2x-3)

The x-intercepts are -4, 0, +1.5.

_____

If you want to solve this "by hand", you can first of all recognize that since there is an x-intercept at 0, the cubic will only have three coefficients. That is, you can write the equation as

... f(x) = ax³ + bx² + cx

Substituting the given points (except (0, 0)) gives three linear equations in a, b, c.

... -a +b -c = 15 . . . . . for x=-1

... a + b + c = -5 . . . . for x=1

... 8a +4b +2c = 12 . . for x=2

adding the first two equations gives 2b=10, or b=5. Now, you can reduce the system to

... a + c = -10

... 4a +c = -4

Subtracting the first of these equations from the second gives 3a=6, or a=2. That tells you c=-12 (from a+c=10).

Then your equation is

... f(x) = x(2x² +5x -12)

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_____

Since the input values are sequential, you can also develop the function from differences of the output values. Those are 15, 0, -5, 12. First differences are -15, -5, +17. Second differences are +10, +22. The third difference is 12. Using the first of these differences in appropriate places in the interpolating polynomial formula, we have

... f(x) = 15 + (x+1)(-15 + (x)/2·(10 + (x-1)/3·(12))) = 2x³ +5x² -12x . . . . as above

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