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Dominik [7]
3 years ago
9

Can someone please help? I will mark brainlist!!!!

Mathematics
1 answer:
elena55 [62]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Because it moves 6 down and 6 right

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Find Percent of a Number - Instruction - Level F
dimaraw [331]

Answer:

Sierra's team has a greater percent of left-handed batters.

25% of Sierra's team bat left handed and 20% of Aubrey's team bat left handed.

Step-by-step explanation:

Sierra: 7/28 = 1/4

1/4 written as a percentage is 25%

Aubrey: 5/25 = 1/5

1/5 written as a percentage is 20%

25% is greater than 20%, so Sierra's team has a greater percent of left-handed batters.

25% of Sierra's team bat left handed and 20% of Aubrey's team bat left handed.

Hope this helps ;)

6 0
3 years ago
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NEED HELP, LIMITED TIME, HURRY
11111nata11111 [884]

Answer:

9

Step-by-step explanation:

here you go!

6 0
3 years ago
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I don't know what to write! Help me please​
Andrews [41]
Sorry, can not see the full picture, try uploading the full image of the question.
3 0
4 years ago
Sherman has 4 cats and 1 dog. He wants to buy a toy for each of his pets. Sherman has $46 to spend on
ANEK [815]

Answer:

spend 8 bucks on cats then left over for the dog

Step-by-step explanation:

3 0
4 years ago
An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

  • a = 10
  • b = 16
  • c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0
3 years ago
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