We are given with
a1 = 2
r = 4
These are components of a geometric series. The first term is 2 and the common ratio is 4. To get the first six terms, we use the formula:
an = a1 r^(n-1)
a1 = 2 (4)^(1-1) = 2
a2 = 2 (4)^(2-1) = 8
a3 = 2 (4)^(3-1) = 32
a4 = 2 (4)^(4-1) = 128
a5 = 2 (4)^(5-1) = 512
a6 = 2 (4)^(6-1) = 2048
5 m/sec or 300m / min
using speed = 
change 5 min 20 sec to seconds = (5 × 60) + 20 = 320 sec
speed =
= 5m / second or
speed = 60 × 5 = 300m / minute
Answer:
C
Step-by-step explanation:hope this helps have a great day =D
Answer:
Perimeter of a square=circumference of circle
4×22=2πr
44=πr
r=14
Area of circle=πr2
22/7×14×14
28×22
616
Answer:
a = 2, b = 3.5
Step-by-step explanation:
Expanding
using Binomial expansion, we have that:
=


We have that the coefficients of the first two terms are 128 and -224.
For the first term:
=>
=> ![a = \sqrt[7]{128}\\ \\\\a = 2](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B7%5D%7B128%7D%5C%5C%20%5C%5C%5C%5Ca%20%3D%202)
For the second term:

Therefore, a = 2, b = 3.5