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4 years ago

42r^2s^4/14r^2s^2z^4

Mathematics

2 answers:

ser-zykov [4K]4 years ago

8 0

Answer 3s^2 / z^4

Subtract the exponents four.s on top cancel with two on bottom leaves two s on top

shutvik [7]4 years ago

4 0

12 is your answer
you are welcoe

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(k^2-6k^4)-(3k^4+k^2+2)

jeka57 [31]

Step-by-step explanation:

Vamos simplificar passo a passo.

k2-6k4-(3k4+k2+2)

Distribua o sinal negativo:

=k2-6k4+-1(3k4+k2+2)

=k2+-6k4+-1(3k4)+-1k2+(-1)(2)

=k2+-6k4+-3k4+-k2+-2

Combine os termos semelhantes:

=k2+-6k4+-3k4+-k2+-2

=(-6k4+-3k4)+(k2+-k2)+(-2)

=-9k4+-2

Responda:

=-9k4-2

7 0

3 years ago

_____ a sequence in which a fixed amount is added on to get the next term

Mariana [72]

Answer: Arithmetic

Explanation:
An Arithmetic Sequence is when a fixed amount is getting added on to the next term, which basically means it is adding a number at a constant rate.

5 0

3 years ago

Please answer the questions

Naily [24]

Answer:

1/18

Step-by-step explanation:

$( {2}^{ - 3} \times {16}^{ \frac{1}{2} } ) \div ( {81}^{ \frac{3}{4} } \times {27}^{ - \frac{1}{3} } ) \\ \\ =( {2}^{ - 3} \times {2}^{ \frac{4 \times 1}{2} } ) \div ( {3}^{ \frac{4 \times 3}{4} } \times {3}^{ - \frac{3 \times 1}{3} } ) \\ \\=( {2}^{ - 3} \times {2}^{ 2} ) \div ( {3}^{ 3 } \times {3}^{ - 1 } ) \\ \\=( {2}^{ - 3 + 2} ) \div ( {3}^{ 3 - 1 } ) \\ \\ = {2}^{ - 1} \div {3}^{2} \\ \\ = \frac{1}{2} \times \frac{1}{9} \\ \\ = \frac{1}{18}$

5 0

3 years ago

Simplify this expression 3xy + 10xy - 5x + 2x - 2yx? Re-write the equations so that like terms are together. (Remember that orde

Elenna [48]

First you have to find the like terms
3xy + 10xy - 2xy and -5x + 2x
After that you solve for the like terms to find the final answer
11xy-3x

6 0

3 years ago

The area of a circle is less than 64 π. which of the following can be the circumference of the circle? (select one or more answe

Solnce55 [7]

Answer:

d. 32 π

Step-by-step explanation:

As given

Area of circle = 64 π

Area of circumference = 1/2*(Area of circle)

Area of circumference = 1/2*(64π)

Area of circumference = 0.5*64π

Area of circumference = 32π

4 0

3 years ago

Read 2 more answers