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4 years ago

I need help getting the answer

Mathematics

1 answer:

Oksi-84 [34.3K]4 years ago

7 0

Answer:

b^2-16 , 16a^2-4

Step-by-step explanation:

m^2+36 is not a difference its a sum so that is automatically ruled out

3x^2-4, 3 isn't a squared number so it can not be used

b^2-16 , is a difference of squares - (b-4)(b+4)

16a^2-4, is also a difference of squares - (4a-2)(4a+2)

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The average rate of change of f from 2 to 3

vodomira [7]

For a function of $f$ , the average rate of change can be found as follows:

$ARC=\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}$

So, this problem asks for the Average Rate of Change of $f$ from $x_{1}=2$ to $x_{2}=3$ . In this way, we need to find $f(x_{1}) \ and \ f(x_{2})$ . As you can see above, we have the graph of $f(x)$ , so we can find these values. Thus, from the graph:

$f(x_{1})=4 \\ f(x_{2})=1$

Therefore:

$ARC=\frac{1-4}{3-2} \\ \\ \therefore \boxed{ARC=-3}$

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4 years ago

Simplify. 12x^4y^5+8x^3y^7-16x^2y^6 over 4xy^5

Rina8888 [55]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

2 in 1

ollegr [7]

1)
2x^2 - 13x - 24 = 0;
the discriminant is : ( - 13 )^2 - 4 * 2 * ( -24 ) = 169 + 192 = 361 = 19^2 => we have two different rational-number solutions ;

2)
[ -2( x + 2 ) - 3( x - 5 ) ] / [ ( x - 5 )( x + 2 ) ] < 0 <=>

( -5x + 11 ) /  [ ( x - 5 )( x + 2 ) ] < 0

We have 2 situations :
a) - 5x + 11 < 0 and  ( x - 5 )( x + 2 ) > 0 => x∈ ( 11 / 5 , + oo ) and x∈( -oo, - 2 )U
( 5 , + oo ) => x∈( 5, +oo);
b)   - 5x + 11 > 0 and  ( x - 5 )( x + 2 ) < 0 => x∈(-oo, 11/5) and x∈( -2, 5 ) =>
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Finally, x∈ U (-2, 11 / 5 ) U ( 5, +oo).

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3 years ago

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OLEGan [10]

Step-by-step explanation:

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6 0

3 years ago

A total of 937 people attended the play admission was $2.00 for adults and $0.75 for students. The total ticket sales amounted t

mamaluj [8]

612 students attended and 325 adults attended the play

<h3><u>Solution:</u></h3>

Let "s" be the number of students attended the play

Let "a" be the number of adults attended the play

Cost of 1 adult ticket = $ 2

Cost of 1 student ticket = $ 0.75

<em><u>Given that total 937 people attended the play</u></em>

number of students + number of adults = 937

s + a = 937 ---------- eqn 1

<em><u>The total ticket sales amounted to $1,109</u></em>

number of adults x Cost of 1 adult ticket + number of students x Cost of 1 student ticket = 1109

$a \times 2 + s \times 0.75 = 1109$

2a + 0.75s = 1109 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

s = 937 - a -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

2a + 0.75(937 - a) = 1109

2a + 702.75 - 0.75a = 1109

1.25a = 1109 - 702.75

1.25a = 406.25

$a = \frac{406.25}{1.25}$

From eqn 3,

s = 937 - 325

Thus 612 students attended and 325 adults attended the play

3 0

3 years ago