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Nitella [24]
3 years ago
12

I need help getting the answer

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0

Answer:

b^2-16 , 16a^2-4

Step-by-step explanation:

m^2+36 is not a difference its a sum so that is automatically ruled out

3x^2-4, 3 isn't a squared number so it can not be used

b^2-16 , is a difference of squares - (b-4)(b+4)

16a^2-4, is also a difference of squares - (4a-2)(4a+2)

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A tailor uses
dimaraw [331]

Answer:

2.5 yards

Step-by-step explanation:

75÷30=2.5 yards

Hope this helps!

5 0
2 years ago
Read 2 more answers
Simplify:<br> 2(xy - 7) = [?]<br> x = -1 and y = 3
fiasKO [112]

Answer:2(xy-7)= -20

Step-by-step explanation:

Plug in -1 for x and 3 for 3, as the question says that x and y represent those values.

2(xy-7) = ?

2((-1)(3) - 7) = ?

2(-3-7)=?

2(-10)

-20

2(xy - 7) = -20

5 0
3 years ago
Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form. What is the value of c in her equation
Zolol [24]

Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form

The standard form of quadratic equation is

y= ax^2 + bx + c

When y=0 then the standard equation becomes

0= ax^2 + bx + c

Now we compare the given equation 0 = -x^2 + 4x - 7  with 0= ax^2 + bx + c and find the value of a, b,c

-x^2 can be written as -1x^2

0= ax^2 + bx + c

0 = -1x^2 + 4x - 7

a= -1 , b=4  and c=-7

The value of c is -7

4 0
3 years ago
Read 2 more answers
Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every
Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}

For machine B:

B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }

The <em>bolts</em> unit cancell each other and we are left with <em>seconds</em>

t = \frac{200}{8} s = 25 s

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

Greetings!

4 0
3 years ago
Read 2 more answers
1.What is the value of log3 729?
xxMikexx [17]
I believe the value of log3 729 is 6

3 0
2 years ago
Read 2 more answers
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