Answer:
I₂ + H₂O --------→ HI + HIO
Explanation:
Iodine is not fully dissolve in water but only dissolve up to some extent.
When iodine was mixed with water it give mixture of two products.
- Hydrogen iodide or hydroiodic acid (HI)
- Hypoiodous acid (HIO)
So the balance reaction is as under
I₂ + H₂O --------→ HI + HIO
All the reactant are one mole and one one mole of each product produced in the shown reaction.
This is a reversible reaction and only 0.05% of Iodine molecule react with water and the other Iodine molecule remain in water unreacted.
Answer:
27.98g/mol
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
T = temperature (K)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
According to the information given:
V = 2.5L
P = 1.4 atm
T = 282K
n = ?
Using PV = nRT
n = PV/RT
n = 1.4 × 2.5/0.0821 × 282
n = 3.5/23.1522
n = 0.151mol
Using the formula to calculate molar mass of the elemental gas:
mole = mass/molar mass
Molar mass = mass/mole
Molar mass = 4.23g ÷ 0.151mol
Molar mass = 27.98g/mol
To assume the empirical formula of a compound, you want the ratio of the moles of every element, and you discover that by means of the percent’s of the element as the element's mass.
As an instance, if a compound is 16% Carbon and 84% sulfur, you can round about that if you had a 100 gram sample of the compound, it would contain 16 grams of carbon & 84 grams of sulfur.
To look for the moles of carbon in that sample, you would distribute the mass by the atomic mass of carbon, so 16/12 = 1.3 moles. You do the similar calculation with the other elements. For Sulfur, you divide 84g by the atomic mass of sulfur, so 84/32 = 2.6moles of sulfur. You endure in this same way if there is more than 2 elements.
Lastly you find the ratio of the moles of every element. The unassuming way to do this is to look the element with the smallest number of moles and split the other moles by that number. In the above example 2.6 moles of Sulfur divided by 1.3 moles of Carbon equals 2. (Which is a 2:1 ratio) Therefore there is twice as numerous sulfurs as carbons in this compound, and the empirical formula is CS2.
