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faust18 [17]
3 years ago
6

Lily took 6 hours to complete a journey at an average speed of 58 km/h. For the first 4 hours, she travelled at an average speed

of 64 km/h. What was the distance for the rest of the journey? km​
Physics
1 answer:
disa [49]3 years ago
3 0

Answer:

92 km

Explanation:

Total distance = 6 x 58 = 348 km

Distance travelled in first 4 hours

= 4 x 64

= 256 km

Distance for rest of journey = 348 - 256 = 92 km

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What vertical distance Δy does a free-falling particle travel from the moment it starts to the moment it reaches a speed of 7.9
mr_godi [17]

Answer:

3.2 m

Explanation:

The equation to use to solve this problem is:

v_f^2 = v_i^2 + 2 a \Delta y

where

v_f is the final velocity

v_i is the initial velocity

a is the acceleration

\Delta y is the distance covered

For the particle in free-fall in this problem, we have

v_i = 0 (it starts from rest)

v_f = 7.9 m/s

g=9.8 m/s^2 (acceleration due to gravity)

By re-arranging the equation, we can find the distance travelled:

\Delta y = \frac{v_f^2 -v_i^2}{2a}=\frac{(7.9 m/s)^2-0^2}{2(9.8 m/s^2)}=3.2 m

5 0
4 years ago
Which of the following is an SI base unit for measuring length?
irina [24]
Meters it the SI unit for measuring length.
6 0
4 years ago
Read 2 more answers
a man stands in a lift going downward with uniform velocity. he experiences a loss of weight at the start but not when lift is i
AnnyKZ [126]

Answer:

It is explained in the explanation section

Explanation:

When the lift starts going downwards, it will start accelerating downwards. After a while, it will start moving with a constant velocity.

Constant velocity means that acceleration is zero and so the man will not feel any weight loss.

Now, Once the lift achieves constant velocity the acceleration is zero hence he will not experience any weight loss.

However, when the lift is in uniform motion, the lift and the man will fall down with an acceleration(a) that is less than that due to gravity(g) . Thus, the man will feel an apparent weight F which is not equal to zero.

6 0
4 years ago
A 60 kg box is lifted by a rope a distance of 10 meters straight up at constant speed. how much power is required to complete th
Nadya [2.5K]
Power=Work/Time
The work done is the energy required to lift the box, fighting the force of gravity. So, Work=Potential energy of the box at 10 meters.

W=PE=mgh=(60)(9.8)(10)=5880J
Finally,
P=W/T=(5880)/(5)=1176Watt

So the answer is 1176 Watts
3 0
3 years ago
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In order to open the clam it catches, a seagull will drop the clam repeatedly onto a hard surface from high in the air until the
Vedmedyk [2.9K]

Answer:

2.2 s

Explanation:

Hi!

Let's consider the origin of the coordinate system at the ground, and consider that the clam starts with zero velocity, the equation of motion of the clam is given by

x(t) = 23.1 m - \frac{1}{2}(9.8 m/s^2) t^2

We are looking for a time t for which x(t) = 0

0 = 23.1 m - (4.9 m/s^2) t^2

Solving for t:

t = \sqrt{\frac{23.1}{4.9}} s = 2.17124 s

Rounding at the first decimal:

t = 2.2 s

4 0
3 years ago
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