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3 years ago

If a vehicle accelerating at 2.7 m/s2what is it's velocity at 20 meters 12.63m/s,1.03m/s,10.39m/s,6.39m/s

Physics

1 answer:

netineya [11]3 years ago

5 0

Answer:

The final velocity of the vehicle is 10.39 m/s.

Explanation:

Given;

acceleration of the vehicle, a = 2.7 m/s²

distance moved by the vehicle, d = 20 m

The final velocity of the vehicle is calculated using the following kinematic equation;

v² = u² + 2ah

v² = 0 + 2 x 2.7 x 20

v² = 108

v = √108

v = 10.39 m/s

Therefore, the final velocity of the vehicle is 10.39 m/s.

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While driving on a rural road, your right wheels run off the pavement. You should hold the steering wheel firmly and

Vsevolod [243]

Answer:

The answer is C. Steer in a straight line while gently slowing down

Explanation:

The following are advised when your cars go off the pavement while driving;

firstly, Do not panic.

ensure you hold on to your steering wheel tightly.

keep Steering straight ahead.

ensure you Stay on the shoulder.

Ease up on the accelerator and brake gently.

When you know you can safely do so, turn back on the road at a much lower speed.

3 0

2 years ago

An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see

mash [69]

Answer:

(7.90 × 10⁻¹⁵) J

Explanation:

The electric force exerted on the elecrron by rhe electric field is given by

F = qE

where |q| = charge on the particle = (1.602 × 10⁻¹⁹) C

E = magnitude of the electric field = (2.9 × 10⁶) V/m or N/C

F = 1.602 × 10⁻¹⁹ × 2.9 × 10⁶ = (4.646 × 10⁻¹³) N

From Newton's first law of motion relation, we can obtain the acceleration this force confers on the electron

F = ma

m = mass of the electron = (9.11 × 10⁻³¹) kg

a = acceleration of the electron caused by the electric force = ?

(4.646 × 10⁻¹³) = (9.11 × 10⁻³¹) × a

a = (4.646 × 10⁻¹³)/(9.11 × 10⁻³¹)

a = (5.10 × 10¹⁷) m/s²

Now, using the equations of motion, we can obtain the velocity with which the electron reaches the positive plate

u = initial velocity of the electron = 0 m/s (since the electron was initially at rest)

v = final velocity of the electron = ?

a = acceleration of the electron = (5.10 × 10¹⁷) m/s²

y = distance covered by the electron = 1.7 cm = 0.017 m

v² = u² + 2ay

v² = 0² + 2(5.10 × 10¹⁷)(0.017)

v² = (1.734 × 10¹⁶)

v = 131,677,182.5 m/s = (1.32 × 10⁸) m/s

Kinetic energy with which the electron hits the positive plate = (1/2)(m)(v²) = (1/2)(9.11 × 10⁻³¹)(1.32 × 10⁸)² = (7.90 × 10⁻¹⁵) J

Hope this Helps!!!

3 0

2 years ago

When you whirl a can at the end of a string in a circular path, what is the direction of the force that acts on the can

andreyandreev [35.5K]

Answer:

Toward the centre of the circular path

Explanation:

The can is moved in a circular path: this means that it is moving by circular motion (uniform circular motion if its tangential speed is constant).

In order to keep a circular motion, an object must have a force that pushes it towards the centre of the circular trajectory: this force is called centripetal force, and its magnitude is given by

$F=m\frac{v^2}{r}$

where m is the mass of the object, v its tangential speed, r the radius of the trajectory. This force always points towards the centre of the circular path.

3 0

2 years ago

Three forces are applied to a solid cylinder of mass 12 kg (see the drawing). The magnitudes of the forces are F1 = 15 N, F2 = 2

crimeas [40]

Answer:

α = 13.7 rad / s²

Explanation:

Let's use Newton's second law for rotational motion

∑ τ = I α

we will assume that the counterclockwise turns are positive

F₁ 0 + F₂ R₂ - F₃ R₃ = I α

give us the cylinder moment of inertia

I = ½ M R₂²

α = (F₂ R₂ - F₃ R₃) $\frac{2}{M R_2^2}$

let's calculate

α = (24 0.22 - 13 0.10) $\frac{2}{12 \ 0.22^2}$ 2/12 0.22²

α = 13.7 rad / s²

6 0

2 years ago

A magnetically soft material is placed in a strong magnetic feild. what is the most likely outcome?

myrzilka [38]

So we want to know what will happen if we put a magnetically soft material in a strong magnetic field. A magnetically soft material is a material whose magnetic field can easily be reversed. Those are ferromagnetic materials. Iron is such a material. When a magnetically soft material is placed into a strong magnetic field it gets its own magnetic field. But its not a permanent magnetic field, it can be changed by a different strong magnetic field.

5 0

2 years ago