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yawa3891 [41]
3 years ago
11

If a vehicle accelerating at 2.7 m/s2what is it's velocity at 20 meters 12.63m/s,1.03m/s,10.39m/s,6.39m/s

Physics
1 answer:
netineya [11]3 years ago
5 0

Answer:

The final velocity of the vehicle is 10.39 m/s.

Explanation:

Given;

acceleration of the vehicle, a = 2.7 m/s²

distance moved by the vehicle, d = 20 m

The final velocity of the vehicle is calculated using the following kinematic equation;

v² = u² + 2ah

v² = 0 + 2 x 2.7 x 20

v² = 108

v = √108

v = 10.39 m/s

Therefore, the final velocity of the vehicle is 10.39 m/s.

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Answer:

Gene therapy is an experimental form of treatment that uses gene transfer of genetic material into the cell of a patient to cure the disease. The idea is to modify the genetic information of the cell of the patient that is responsible for a disease, and then return that cell to normal conditions.

Explanation:

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A 5.00 kg pendulum swings back and forth. At the top of its arc it reaches a height of 0.36 m. What is the velocity of the pendu
azamat

Answer:

Gravitational potential energy = (mass) x (gravity) x (height)

Kinetic energy (of a moving object) = (1/2) (mass) x (speed)²

When the pendulum is at the top of its swing, its potential energy is

(mass) x (gravity) x (height)

= (5 kg) x (9.8 m/s²) x (0.36 m)

= (5 x 9.8 x 0.36) joules

17.64 joules .

Energy is conserved ... it doesn't appear or disappear ... so that number is exactly the kinetic energy the pendulum has at the bottom of the swing, only now, it's kinetic energy:

17.64 joules = (1/2) x (mass) x (speed)²

17.64 joules = (1/2) x (5 kg) x (speed)²

Divide each side by 2.5 kg:

17.64 joules / 2.5 kg = speed²

Write out the units of joules:

17.64 kg-m²/s² / 2.5 kg = speed²

(17.64 / 2.5) (m²/s²) = speed²

7.056 m²/s² = speed²

Take the square root of each side: Speed = √(7.056 m²/s²) = 2.656 m/s.

Looking through the choices, we're overjoyed to see that one if them is ' 2.7 m/s '. Surely that's IT !

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3 years ago
What is the loudness, in decibels, of a sound 1 trillion times as loud as the softest audible sound?
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Answer:

What is the loudness, in decibels, of a sound 100 trillion times as loud as the softest audible sound? The loudness of this sound in decibels is dB. (Type an integer or a decimal.)

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How does the​ long-run equilibrium for a monopolistically competitive market differ from the​ long-run equilibrium for a perfect
Katen [24]

Answer and Explanation:

The main difference between monopolistic competition and perfect competitive market are given bellow

Excess capacity : There is constantly an overabundance limit in monopolistic challenge and not in the ideal challenge. Over the long haul, superbly aggressive firms produce at the proficient scale,where as monopolistically focused firms produce beneath this level. Firms are said to have abundance limit under monopolistic challenge. As it were, a monopolistically focused firm, in contrast to a splendidly aggressive firm, could build the amount it delivers and lower the normal all out expense of generation.

Markup over marginal cost:   the another distinction between flawless challenge and monopolistic challenge is the connection among cost and minor expense. At an aggressive firm consistently cost equivalents negligible expense. Where as, in monopolistically aggressive firm, cost surpasses minimal expense becouse the firm consistently have some market control.

3 0
3 years ago
Consider a 30-cm-diameter hemispherical enclosure. The dome is maintained at 600 K, and heat is supplied from the dome at a rate
SIZIF [17.4K]

Answer:

\epsilon_2=0.098

Explanation:

Diameter d=30cm=0.3m

Temperature T=600k

Rate of supply r=65W

Emissivity of base surface \in_b =0.55

Temperature at base T_b=400k

Generally the equation for Area of base surface is mathematically given by

 A_b=\frac{\pi}{4}d^2

 A_b=\frac{\pi}{4}0.3^2

 A_b=0.0707m^2

Generally the equation for Area of Hemispherical dome is mathematically given by

 A_h=\frac{\pi}{2}d^2

 A_h=\frac{\pi}{2}0.3^2

 A_h=0.1414m^2

Since base is a flat surface

 F_{11}+F_{12}=1

 F_{11}=0

Therefore

 F_{12}=1

 A_b=0.0707m^2

Generally the equation for Net rate of radiation heat transfer between two surfaces is mathematically given by

 Q_{21}=-Q_{12}

 Q_{21}=\frac{\sigma(T_1^4-T_2^4)}{\frac{1-\epsilon}{A_b\epsilon_1} +\frac{1}{A_bF_{12}} +\frac{1-\epsilon_2}{A_h*\epsilon_2} }

Where

 \sigma=5.67*10^{-8}

Therefore

  65=\frac{(5.67*10^{-8}(400^4-600^4))}{\frac{1-0.55}{0.0707*0.55}+\frac{1}{0.0707}+\frac{1-\epsilon_2}{0.1414*\epsilon_2}}

 \epsilon_2=0.098

 \epsilon_2 \approx 0.1

Therefore  the emissivity of the dome is

 \epsilon_2=0.098

3 0
3 years ago
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