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andrew-mc [135]
3 years ago
10

Imagine that a relativistic train travels past your lecture room at a speed of 0.894 c. The passengers of the train claim that w

hen they measure the length of the train using standard meter bars found on the train, the length comes out to be 90.6 m. What would be the length of the train in the frame of the lecture room, if you measured it?
Physics
1 answer:
Lady bird [3.3K]3 years ago
8 0

Answer:

The length of the train in the frame of the lecture room is 40.59 m.

Explanation:

Given that,

Speed = 0.894 c

Original length = 90.6 m

We need to calculate the length of the train in the frame of the lecture room

Using formula of length contraction

L=L_{0}\sqrt{1-(\dfrac{v}{c})^2}

Where, L_{0}=original length

v = speed of train

Put the value into the formula

L=90.6\sqrt{1-(\dfrac{0.894c}{c})^2}

L=90.6\sqrt{1-0.894^2}

L=40.59\ m

Hence, The length of the train in the frame of the lecture room is 40.59 m.

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Answer:

I would believe that it would be the last option

Explanation:

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4 0
2 years ago
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An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of 25.0 with the horizontal. The coeffici
uranmaximum [27]

Answer:

V = 10.88 m/s

Explanation:

V_i =initial velocity = 0m/s

a= acceleration= gsinθ-\mu_kcosθ

putting values we get

a= 9.8sin25-0.2cos25= 2.4 m/s^2

v_f= final velocity and d= displacement along the inclined plane = 10.4 m

using the equation

v^2_f=v^2_i-2as

v^2_f=0^2-2(2.4)(10.4)

v_f= 7.04 m/s

let the speed just before she lands be "V"

using conservation of energy

KE + PE at the edge of cliff = KE at bottom of cliff

(0.5) m V_f^2 + mgh = (0.5) m V^2

V^2 = V_f^2 + 2gh

V^2 = 7.04^2 + 2 x 9.8 x 3.5

V = 10.88 m/s

6 0
3 years ago
A 13,000 kg helicopter accelerates upward a 0.5 m/s^2 while lifting a 2000 pound car. to the nearest newton, what is the lift fo
Vinil7 [7]

Lift force exerted by the air on the rotors=143244 N

Explanation:

we use Newtons second law

F- (M+m)g=(M+m)a

F= lift force

m= mass of helicopter= 13000 Kg

M= mass of car= 2000 lb=907.2 kg

a= acceleration= 0.5 m/s²

g= acceleration due to gravity

F- (M+m)g=(M+m)a

F=(M+m)(a+g)

F=(13000+907.2)(0.5+9.8)

F=143244 N

8 0
3 years ago
Spiderman has a mass of 80 kg. He knows his webbing will break if it is exposed to a 200 N force. What is the maximum height he
likoan [24]

Answer:

This depends on the writers

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8 0
3 years ago
A mass of 5 kg of saturated water vapor at 150 kPa is heated at constant pressure until the temperature reaches 200°C. Calculate
yulyashka [42]

Answer:

The work done by the steam is 213 kJ.

Explanation:

Given that,

Mass = 5 kg

Pressure = 150 kPa

Temperature = 200°C

We need to calculate the specific volume

Using formula of work done

W=Pm\DeltaV

W=Pm(\dfrac{RT_{1}}{P_{atm}}-\dfrac{RT_{2}}{P_{atm}}

W=\dfrac{PmR}{P_{atm}}(T_{2}-T_{1})

Where,R = gas constant

T = temperature

P = pressure

P_{atm}=Atmosphere pressure

m = mass

Put the value into the formula

W=\dfrac{150\times10^{3}\times5\times287.05}{1.01\times10^{5}}\times(473-373)

W=213\ kJ

Hence, The work done by the steam is 213 kJ.    

6 0
3 years ago
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