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andrew-mc [135]
3 years ago
10

Imagine that a relativistic train travels past your lecture room at a speed of 0.894 c. The passengers of the train claim that w

hen they measure the length of the train using standard meter bars found on the train, the length comes out to be 90.6 m. What would be the length of the train in the frame of the lecture room, if you measured it?
Physics
1 answer:
Lady bird [3.3K]3 years ago
8 0

Answer:

The length of the train in the frame of the lecture room is 40.59 m.

Explanation:

Given that,

Speed = 0.894 c

Original length = 90.6 m

We need to calculate the length of the train in the frame of the lecture room

Using formula of length contraction

L=L_{0}\sqrt{1-(\dfrac{v}{c})^2}

Where, L_{0}=original length

v = speed of train

Put the value into the formula

L=90.6\sqrt{1-(\dfrac{0.894c}{c})^2}

L=90.6\sqrt{1-0.894^2}

L=40.59\ m

Hence, The length of the train in the frame of the lecture room is 40.59 m.

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Sphinxa [80]

Answer: \frac{V^{2}}{r}

Explanation:

According to Newton's 2nd Law of motion the force F is proportional to the mass Fm and acceleration a:

F=m.a (1)

On the other hand, the equation for the Centripetal force is:

F=\frac{mV^{2}}{r} (2)

Where:

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Making (1) and (2) equal:

m.a=\frac{mV^{2}}{r} (3)

Hence:

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During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ±
Alla [95]

Answer:

P = 1 (14,045 ± 0.03 )  k gm/s

Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

            Δ (Pₓ / Py) =?

 Let's start by finding the momentum of each vehicle

car X

        Pₓ = m vₓ

        Pₓ = 2.34 2.5

        Pₓ = 5.85 kg m

car Y

        Py = 2,561 3.2

        Py = 8,195 kgm

How do we calculate the absolute uncertainty at the two moments?

          ΔPₓ = m Δv + v Δm

          ΔPₓ = 2.34 0.01 + 2.561 0.01

          ΔPₓ = 0.05 kg m

         ΔP_{y} = m Δv + v Δm

         ΔP_{y} = 2,561 0.01+ 3.2 0.001

         ΔP_{y} = 0.03 kg m

now we have the uncertainty of each moment

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          ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²

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          ΔP = 0.009 kg m

The result is

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