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Dimas [21]
2 years ago
15

Which change in a limiting factor would increase the carrying capacity for earthworms on the ground of a mixed-oak forest? A. in

crease in the fern population size B. decrease in the ant population size C. increase in the grass population size D. decrease in the ovenbird population size
Physics
1 answer:
OLEGan [10]2 years ago
7 0

I think its A. increase in the fern population size. For the answer.

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A girl is floating in a freshwater lake with her head just above the water. If she weighs 610 N, what is the volume of the subme
Elden [556K]

Answer:

The volume of the submerged part of her body is 0.0622m^{3}

Explanation:

Let's define the buoyant force acting on a submerged object.

In a submerged object acts a buoyant force which can be calculated as :

B=ρ.V.g

Where ''B'' is the buoyant force

Where ''ρ'' is the density of the fluid

Where ''V'' is the submerged volume of the object

Where ''g'' is the acceleration due to gravity

Because the girl is floating we can state that the weight of the girl is equal to the buoyant force.

We can write :

W_{girl}=B (I)

Where ''W'' is weight

⇒ If we consider ρ = 1000\frac{kg}{m^{3}} (water density) and g=9.81\frac{m}{s^{2}} and replacing this values in the equation (I) ⇒

B=W_{girl}

B=610N

ρ.V.g = 610N

1000\frac{kg}{m^{3}}.V.(9.81\frac{m}{s^{2}})=610N (II)

The force unit ''N'' (Newton) is defined as

N=kg.\frac{m}{s^{2}}

Using this in the equation (II) :

(9810\frac{N}{m^{3}}).V =610N

V=\frac{610N}{9810\frac{N}{m^{3}}}

V=0.0622m^{3}

We find that the volume of the submerged part of her body is 0.0622m^{3}

8 0
3 years ago
Importance of electrical symbol​
Vsevolod [243]
The electrical symbols are very important especially when fixing electrical appliances because it tells you where the wire of neutral and live go.
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The mass of a triton is
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2.14x 1022 kg 

the 22 is a xponet of ten
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Briana pushed a 5 kg box of dance flyers with a force of 10 N. What is the acceleration of the box?
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Answer:

Explanation:

From force =ma

a=f/m

a=10/5

a=2m/s2

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2 years ago
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On your drive home from school, you travel 1200 m in 80 s, then 400 min 20 s.
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Average speed = Total distance/total time taken

=  \frac{1200 + 400}{80 + 20}

=  \frac{1600}{100}

=  \frac{16}{1}

= 16 \: ms {}^{ - 1}

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3 years ago
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