The probability of drawing a goldfish on the first draw is 16 / ( 16 + 24 ), or 16/40, or 2/5. Supposing that the first fish drawn is actually a goldfish, then there are 15 goldfish left among 39 fish, and the probability of drawing a goldfish on the 2nd draw is 15/39, or 5/13. The (joint) probability of drawing 2 goldfish on the 1st 2 draws, without replacement, is (5/13)(2/5) = 2/13.

5 0

3 years ago

M∠AKG = 133°. <br> What is m∠AKD?<br><br> m∠AKD = [1] °

xenn [34]

AKG-DKG=AKD
133°-87°=46°

4 0

3 years ago

Circle the possible values that satisfy this inequality X - 3 < 9

horsena [70]

4-3<9
5-3<9
6-3<9
and so on...

3 0

3 years ago

Use the given minimum and maximum data entries, and the number of classes, to find the class width, the lower class limits,

Georgia [21]

Answer:

Step-by-step explanation:

Given that minimum is 8 and maximum equals 82

Range = $84-8 = 76$

No of classes =6

Class width = 76/6 ~13

But not given whether variable is discrete or continuous.

If discrete, we have classes as

8-20, 21-33, 34-46, 47-59, 60-72, 73-85

If continuous, we have classes as

8 to <21

21 to <34

and ... ending 73-<86

7 0

3 years ago