Let's solve for x.
2x−9y=14
Step 1: Add 9y to both sides.
2x−9y+9y=14+9y
2x=9y+14
Step 2: Divide both sides by 2.
2x
/2
=
9y+14
/2
x=
9
/2
y+7
Answer:
Step-by-step explanation:
To write the quadratic in standard form, begin by writing it in vertex form
Where (h,k) is the vertex of the parabola.
Here the vertex is (-3,-2). Substitute and write:
To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.
The vertex form of the equation is 
.
To write in standard form, convert vertex form through the distributive property.
It looks like the first 1 is the first problem, problem #1. (because of the period)
If this is the case, then the second sequence is 1, 0, -1, ...
1-1=0
0-1=-1
-1-1=-2
-2-1=-3
-3-1=-4
The sequence would then be 1, 0, -1, -2, -3, -4, ...
Answer:
The third graph is the graph of the function provided
Step-by-step explanation:
A simple technique that can be used to identify the graph that matches the given function is; determination of the y-intercept and then using elimination method to match the function with its graph. At the y-intercept the value of x is always zero, so we replace x with zero in the right hand side of the equation; y(x) = 2^(0+3) = 8. The graph of the function should therefore cross the y-axis at the point (0,8). Thus, the third graph is the graph of the given function.
8x-12y=84
in slope intersept form or (y=mx+b) is
y=2/3x-7
