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Hitman42 [59]
4 years ago
12

Please help me out please

Mathematics
1 answer:
Scorpion4ik [409]4 years ago
3 0

Answer:

\large\boxed{x=11}

Step-by-step explanation:

Use Angel Bisector Theorem <em>(look at the picture)</em>,

\dfrac{3x-3}{24}=\dfrac{5x}{44}\qquad\text{cross multiply}\\\\44(3x-3)=24(5x)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(44)(3x)+(44)(-3)=120x\\\\132x-132=120x\qquad\text{add 132 to both sides}\\\\132x=120x+132\qquad\text{subtract}\ 120x\ \text{from both sides}\\\\12x=132\qquad\text{divide both sides by 12}\\\\x=11

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Which situation will have the greatest number of permutations?
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Answer:

Option C will have greatest number of permutations.

Step-by-step explanation:

A.

The number of license plates with 4 letters followed by 3 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

23 letter options for 4th letter.

So total options for 4 letters 26*25*24*23 = 358800

Now, 3 numbers are required. We have total 10 numbers (0-9)

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B.

The number of license plates with 3 letters followed by 4 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

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So total options for 3 letters= 26*25*24 = 15600

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C. The number of license plates with 4 letters followed by 3 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 4 letters and 10 options for each 3 numbers

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3 years ago
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Step-by-step explanation:

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