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blagie [28]
2 years ago
6

The function h is defined by h (x) = 2x^2 + 3. Find h(2x)

Mathematics
1 answer:
Tema [17]2 years ago
7 0

h(2) = 2(2^2) + 3

h(2) = 8 + 3

h(2) = 11

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4*10^6 is how many as times as 1*10^4
salantis [7]

4*10^6 = 4,000,000 1*10^4 = 10,000 4,000,000 x 10,000 = 40,000,000,000 ANSWER: 40,000,000,000


6 0
3 years ago
Line w ‖ segment YZ.<br><br> Which angle has the same measurement as ∠3?
zubka84 [21]
< 1 is the angle has the same measurement as < 3 ( alternate interior angles )
4 0
3 years ago
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}&#10;\\\\\\&#10;&#10;\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
5 0
3 years ago
How do I solve this? Step by step
shutvik [7]

Answer:

24.

Step-by-step explanation:

Substitute each instance of x with a 3.

That leaves us with 3^2 + 3x - 5 + 3^2 - 3x + 11.

Combine like terms.

2(3^2) + 6.

Simplify.

2(9) + 6

18 + 6

24.

8 0
2 years ago
Read 2 more answers
Skill Sum
Nataly_w [17]

Answer:

I don't know

Step-by-step explanation:

I don't know

3 0
3 years ago
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