-x-5
  -  -5x^2 - 3
or
(-x-5) - (-5x^2 - 3)
First, distribute the -. So then it becomes
-x - 5 + 5x^2 + 3
Since you can't add 5x^2 to -x. You can only combine -5 and 3.
Thus it becomes
 - x + 5x^2 -2
However, you order in exponents so
5x^2 - x - 2
would be the correct answer.
        
             
        
        
        
Answer:
-6-7ji-20j^(2)
Step-by-step explanation:
 
        
             
        
        
        
5/8 or .625 is the answer                
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
The best way to do this is to use your LCM and eliminate the fractions.  To find the LCM you have to use all the denominators as a multiplier so the denominator in each term cancels out.  We will first factor the x-squared term to simplify and see what 2 factors are hidden there.
 factors to (x + 2)(x - 2).  That means that our 3 denominators that make up our LCM are x(x+2)(x-2).  We will mulitply that in to each term in our rational equation, canceling out the denominators where applicable.
 factors to (x + 2)(x - 2).  That means that our 3 denominators that make up our LCM are x(x+2)(x-2).  We will mulitply that in to each term in our rational equation, canceling out the denominators where applicable.
![x(x+2)(x-2)[\frac{2}{(x-2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}]](https://tex.z-dn.net/?f=x%28x%2B2%29%28x-2%29%5B%5Cfrac%7B2%7D%7B%28x-2%29%7D%2B%5Cfrac%7B7%7D%7B%28x-2%29%28x%2B2%29%7D%3D%5Cfrac%7B5%7D%7Bx%7D%5D)
In the first term, the (x-2) will cancel leaving us with
x(x+2)[2] which simplifies to
![x^2+2x[2]](https://tex.z-dn.net/?f=x%5E2%2B2x%5B2%5D)
In the second term, the (x+2)(x-2) cancels out leaving us with
x[7].
In the last term, the x cancels out leaving us with
(x+2)(x-2)[5] which simplifies to
![x^2-4[5]](https://tex.z-dn.net/?f=x%5E2-4%5B5%5D)
Now we will distribute through each cancellation:
2x²+4x;
7x;
5x²-20
Putting them all together we have
2x² + 4x + 7x = 5x² - 20
Combining like terms gives us a quadratic:
3x² - 11x - 20 = 0
Factor that however you find it easiest to factor quadratics and get that
x = 5 and x = -4/3
 
        
             
        
        
        
The domain is all input values(otherwise known as all x-values on the x-axis) and the range is all possible output values( y-values, as shown on the y-axis). Functions are expressions involving 1 or more variables, in a function x-values are only allowed 1 y-value or else it isn’t considered a function. 
Hope this helps!