Question

Between 1911 in 1990, the top of the leaning bell tower of Pisa, Italy moved toward the south at an average rate of 1.2 MM/Y. The tower is 55M tall. In radians per second, what is the average regular speed of the towers top about its base?

Answer 1

Answer:

Angular speed of the towers top about its base is $6.91\times 10^{-13}$ rad per sec.

Step-by-step explanation:

Linear velocity of leaning bell tower 'v' = 1.2 mm per year

v = $\frac{1.2\times 10^{-3}}{365\times 24\times 60\times 60}$

v = 3.8 × $10^{-11}$ meter per second

Height of the tower = 55 meter

From the formula of angular velocity,

v = rω

ω = $\frac{v}{r}$

ω = $\frac{3.8\times 10^{-11}}{55}$

ω = $6.91\times 10^{-13}$ rad per second.

Therefore, top of the tower is moving with an angular speed of $6.91\times 10^{-13}$ rad per second.