Answer:
<h2>SEE BELOW</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>let's solve:</h3>
vertex:(h,k)
therefore
vertex:(-1,4)
axis of symmetry:x=h
therefore
axis of symmetry:x=-1
- to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0
vertex form of quadratic equation:
therefore
- y=a(x-(-1))²+4
- y=a(x+1)²+4
it's to notice that we don't know what a is
therefore we have to figure it out
the graph crosses y-asix at (0,3) coordinates
so,
3=a(0+1)²+4
simplify parentheses:

simplify exponent:

therefore

our vertex form of quadratic equation is
let's simplify it to standard form
simplify square:

simplify parentheses:

simplify addition:

therefore our answer is D)y=-x²-2x+3
the domain of the function

and the range of the function is

zeroes of the function:




factor out x and -1 respectively:

group:

therefore

-Notice that dividing our numbers leaves no remainder:
1,620 ÷ 5 = 324 + 0
-1,620 has all the factors of the number 5
Answer: 4x² + 5x + 3
<u>Step-by-step explanation:</u>

Answer:
Step-by-step explanation:
Here is a tip: When you have something that looks like this - ( - , turn it into a plus sign. It looks kind of like a plus sign anyway. So if you have 53- (-32), turn it into 53 + 32. Does that make sense?
So 53 + 32 = 85.
Another tip to do it in your head, is to do 50 + 30 = 80, then do 3 + 2 = 5, and add them. It's easier than trying to juggle the odd numbers. :)
Answer:
6
√
(
3
x
+
5
)
(
3
x
−
2
)
Step-by-step explanation: