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3 years ago

For thousand 400 is 10 times as much as 440

Mathematics

2 answers:

ikadub [295]3 years ago

5 0

4400 yay math problems !!!!!!!!!

ss7ja [257]3 years ago

3 0

440 x 10 = 4,400. Yes 4,400 is 10 times as much as 440

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Dairy farmers are aware there is often a linear relationship between the age, in years, of a dairy cow and the amount of milk pr

Jobisdone [24]

Answer:

B. A cow of 5 years is predicted to produce 5.5 more gallons per week.

Step-by-step explanation:

Let $M(a) = 40.8-1.1\cdot a$ , where $a$ is the age of the dairy cow, measured in years, and $M(a)$ is the predicted milk production, measured in gallons per week.

Besides, we consider $a_{1}$ and $a_{2}$ , such that $a_{1}\ne a_{2}$ , we define the difference between predicted milk productions ( $\Delta M$ ) below:

$\Delta M = -1.1\cdot (a_{2}-a_{1})$ (1)

If we know that $a_{1} = 5\,yr$ and $a_{2} = 10\,yr$ , then the difference between predicted milk productions is:

$\Delta M = -1.1\cdot (10-5)$

$\Delta M = -5.5\,\frac{gal}{week}$

That is, a cow of 5 years is predicted to produce 5.5 more gallons per week than a cow of 10 years. Hence, the right answer is B.

6 0

2 years ago

Write the multiplicative inverse of a) -13/19

irga5000 [103]

Answer:

$- \frac{19}{13}$

Step-by-step explanation:

$the \: multiplicative \: inverse \: of \: \\ - \frac{13}{19} = - \frac{19}{13}$

Product of a number and its multiplicative inverse should be equal to 1.

So,

$\bigg ( - \frac{13}{19} \bigg) \bigg ( - \frac{19}{13} \bigg)$

$= \frac{13}{19}\times \frac{19}{13}$

$=1$

3 0

3 years ago

Find the area of the triangle with the given base and height. b = 3 m and h = 10 1/2 m

svetoff [14.1K]

Statement:

The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

To find out:

The area of the triangle.

Solution:

Given, base = 3m, height = $10 \frac{1}{2}$ m
We know,

$\sf \: area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times base \: \times height$

Therefore, the area of the triangle

$\sf = (\frac{1}{2} \times 3 \times 10 \frac{1}{2} ) {m}^{2} \\ \sf = ( \frac{1}{2} \times 3 \times \frac{21}{2} ) {m}^{2} \\ = \sf \frac{63}{4} {m}^{2} \\ = \sf 15\frac{3}{4} {m}^{2}$