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4 years ago

14

For thousand 400 is 10 times as much as 440

2 answers:

ikadub [295]4 years ago

5 0

4400 yay math problems !!!!!!!!!

ss7ja [257]4 years ago

3 0

440 x 10 = 4,400. Yes 4,400 is 10 times as much as 440

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A map has a scale of 2 inches = 15 miles.If two towns are 7 inches apart on the map,how far apart are they actually

seraphim [82]

1.) set up a w_k_u chart
2.) in the w column write in on top and mi in the bottom like this
w_K_U
in_
mi_
then in the k column write 2 for in and 15 for mi
W_K_U
in_2_
mi_15_
then in the U column, you write 7 for in and x for mi
W_K_U
in_2_7
mi_15_x
then cross multiply: 2x = 15(7)
multiply 15 times 7 which is 105
2x=105
divide 2x by 2
x=105
answer 105

3 0

3 years ago

Read 2 more answers

1. Fifty-eight thousandths

kap26 [50]

fifty-eight thousandths?

4 0

3 years ago

What function is equivalent to g(x)=x2+15×-54

anastassius [24]

Answer:

not quite sure the specifc answer of this question at this time

Step-by-step explanation:

3 0

3 years ago

What is the domain and range of the relation shown in the table?

Leokris [45]

Answer:

domain: {-12, -8, 0, 1} range: {0, 8, 12}

Step-by-step explanation:

domain are of all the input values shown on the x-axis. The range is the set of possible output shown on the y-axis.

5 0

3 years ago

A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t

Harman [31]

Answer:

The expectation is $E(1 )= -\$ 1$

Step-by-step explanation:

From the question we are told that

The first offer is $x_1 = \$ 8000$

The second offer is $x_2 = \$ 4000$

The third offer is $\$ 1600$

The number of tickets is $n = 5000$

The price of each ticket is $p= \$ 5$

Generally expectation is mathematically represented as

$E(x)=\sum x * P(X = x )$

$P(X = x_1 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_1 ) = 0.0002$

Now

$P(X = x_2 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_2 ) = 0.0002$

Now

$P(X = x_3 ) = \frac{5}{5000}$ given that they offer five

$P(X = x_3 ) = 0.001$

Hence the expectation is evaluated as

$E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001$

$E(x)=\$ 4$

Now given that the price for a ticket is $\$ 5$

The actual expectation when price of ticket has been removed is

$E(1 )= 4- 5$

$E(1 )= -\$ 1$

4 0

3 years ago