All categories

2 years ago

Please answer this find the circumference for each of them TYSMMM

Mathematics

1 answer:

artcher [175]2 years ago

6 0

For a , C= 18.85
for b , C= 21.99
for 1 , C= 75.4
for 2 , C= 87.96

You might be interested in

If A = {2,4,6,8,}, write the set A by description method

belka [17]

Step-by-step explanation:

Set-builder notation is a notation for describing a set by indicating the properties that its members must satisfy.

C={2,4,6,8}

C={2×1,2×2,2×3,2×4}

thus set builder form is:

{x:x=2n,n∈N} and this set is also call even number set in description mathod

6 0

2 years ago

Can someone explain this question which part of the class do you think you will apply to your life both now or in the future?

stellarik [79]

Ok I understand nununununuununu

3 0

2 years ago

Two-thirds a number plus 4 is 7

ICE Princess25 [194]

The equation (form) is: $\frac{2}{3}x + 4 = 7$

The solution of the equation is: $x = \frac{9}{2}$

Explanation:

First, let's call the number we are going to solve for "x".

Then two thirds of this number can be written as:

$\frac{2}{3}x$

Then "plus 4" means add 4 we get:

$\frac{2}{3}x + 4$

"is 7" means that the above expression is equal to 7 (as follows):

$\frac{2}{3}x + 4 = 7$

The solution of the above equation is:

$\frac{2}{3}x + 4 = 7 \\ \frac{2}{3}x = 3 \\ x = \frac{9}{2}$

6 0

2 years ago

Ameeta finished 12 math problems. David finished 3 times as many. How many more math problems did David finish than Ameeta?

Volgvan

Answer:
david finished 24 problems more than ameetha
Step-by-step explanation:
problems finished by ameetha = 12 problems
problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36
problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =
problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =36-12= 24
problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =36-12= 24 so David finished 24 problems more than ameetha

8 0

3 years ago

Many of you will live to the year 2100, which is not a leap year. Not all years which are divisible by 4 are leap years. A cente

Slav-nsk [51]

Answer:

For example, the years 1600, 2000, and 2400 are century leap years since those numbers are divisible by 400, while 1700, 1800, 1900, 2100, 2200, and 2300 are common years despite being divisible by 4.

Step-by-step explanation:

3 0

2 years ago