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miss Akunina [59]
3 years ago
5

How do I solve P(-5,12)

Mathematics
1 answer:
Tasya [4]3 years ago
7 0
I suppose P is a point that has coordinate  -5 by OX and 12 by OY
                           /\  OY
                            |
        * P(-5,12)     |
                            |
                            |
                            |
                            |
                            |
                            |
                            |
                            |
                            |
                            |
                            |
----------|------------------------------------------>
          -5                                                    OX






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lina2011 [118]
802.11 legacy = 2 Mbps<span>
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7 0
3 years ago
Malcolm and Ravi raced each other. The average of their maximum speeds was 260\text{ km/h}260 km/h260, space, k, m, slash, h. If
nikdorinn [45]

Let m and r represent the maximum speeds of Malcolm and Ravi in km/h, respectively.

... (m + r)/2 = 260 . . . . . the average of their speeds was 260 kph

... 2m = r + 80 . . . . . . . . double Malcolm's speed is 80 kph more than Ravi's

The second equation can be solved for r and that expression substituted into the first equation.

... 2m - 80 = r . . . . . . . . . . . an expression for r from the second equation

... (m + 2m - 80)/2 = 260 . . . the result of substituting that into the first

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Malcolm's maximum speed was 200 km/h.

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6 0
3 years ago
Please help urgent!!
trapecia [35]

Answer:

<em>The area of the rectangle is</em> A=12b^6+6b^3-18b^2

Step-by-step explanation:

<u>Area of a rectangle</u>

A rectangle of height H and width W has an area of:

A=H*W

The rectangle shown in the figure has a height of:

H=3b^2

And a width of

W=4b^4+2b-6

The area is

A=(3b^2)(4b^4+2b-6)

Operating:

A=(3b^2)*4b^4+(3b^2)*2b-(3b^2)6

A=12b^6+6b^3-18b^2

The area of the rectangle is A=12b^6+6b^3-18b^2

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3 years ago
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frozen [14]

Answer:

Wilma has $12.

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We can just replace the x with 3 to get:

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Read 2 more answers
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Answer:

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1.

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2.

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