802.11 legacy = 2 Mbps<span>
802.11a = </span>54 Mbps<span>
802.11b = </span>11 Mbps<span>
802.11g = </span><span>54 Mbps</span>
Let m and r represent the maximum speeds of Malcolm and Ravi in km/h, respectively.
... (m + r)/2 = 260 . . . . . the average of their speeds was 260 kph
... 2m = r + 80 . . . . . . . . double Malcolm's speed is 80 kph more than Ravi's
The second equation can be solved for r and that expression substituted into the first equation.
... 2m - 80 = r . . . . . . . . . . . an expression for r from the second equation
... (m + 2m - 80)/2 = 260 . . . the result of substituting that into the first
... 3m - 80 = 520 . . . . . . . . multiply by 2
... m = 200 . . . . . . . . . . . . . add 80 and divide by 3
... 2·200 - 80 = r = 320 . . .substitute the value of m into the expression for r
Malcolm's maximum speed was 200 km/h.
Ravi's maximum speed was 320 km/h.
Answer:
<em>The area of the rectangle is</em> 
Step-by-step explanation:
<u>Area of a rectangle</u>
A rectangle of height H and width W has an area of:

The rectangle shown in the figure has a height of:

And a width of

The area is

Operating:


The area of the rectangle is 
Answer:
Wilma has $12.
Step-by-step explanation:
Since we don't know how many hours she worked, we know that Wilma earned 9x dollars at her job. Then she spends $15, so we can just subtract 15 from 9x.

We can just replace the x with 3 to get:

Hence, Wilma has $12.
Answer:
Solution given:
Volume of cone=⅓πr²h
Volume of cylinder=πr²h
1.
volume =πr²h=π*(10/2)²*6=<u>471.23mm³</u>
2.
Volume =πr²h=π*8*12.5=<u>314.16in³</u>
3.
volume =⅓πr²h=⅓*π*4²*3=<u>5</u><u>0</u><u>.</u><u>2</u><u>6</u><u>c</u><u>m</u><u>³</u>
4.
Volume =⅓πr²h=⅓*π*(8/2)²*12=<u>2</u><u>0</u><u>1</u><u>.</u><u>0</u><u>6</u><u>i</u><u>n</u><u>³</u>