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VLD [36.1K]
3 years ago
10

What is the equation of the line that is perpendicular to the

Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0

Answer:

Correct Answer: C. y = Four-thirdsx – 8

Step-by-step explanation:

You might be interested in
-2
Elodia [21]

Answer:

It would be the 2nd one

Step-by-step explanation:

4 0
3 years ago
Someone help and please answer it fully
IRINA_888 [86]

Answer:

No, Matt did not solve the equation correctly

Correct Answer: x = 8

Step-by-step explanation:

4(x + 2) = 30

Step 1: Distribute

4x + 2 = 30      =>     This is his mistake, he should completely distribute 4    

                                  to x and 2

Step 2: Subtract 2 from both sides/Isolate x

4x = 28           =>      This part is done correctly, but wrong because of Step 1

Step 3: Divide both sides by 4

x = 7                =>      This is correct, but again, he messed up on Step 1

<h3>Let's find the correct answer to this equation:</h3><h3>4(x +2) = 30</h3>

Step 1: Distribute

Remember to distribute 4 to all terms in the parenthesis.

4(x + 2) = 4(x) + 4(2)

            = 4x + 8

4x + 8 = 30

Step 2: Subtract 8 from both sides/Isolate x

Move all the terms that do not belong to x to the other side. We can do this by subtracting 8 from both sides  => (opposite operation of adding 8)

4x + 8 = 30

4x = 30 - 8

4x = 32

Step 3: Divide both sides by 4/Isolate x

Now we want x by itself. Since x is being multiplied by 4, we have to use the opposite operation, dividing by 4, to have x on one side by itself

4x = 32

4(x) = 32

x = 32 ÷ 4

x = 8

-Chetan K

7 0
2 years ago
S use f(x)=2x-5 and g(x)=4x+3
jeyben [28]

Step-by-step explanation:

can you please add details to your question

7 0
2 years ago
Read 2 more answers
Add (3+2i)+(-5+6i)<br> A) -8+8i<br> B) -8-4i<br> C) -2+8i<br> D) -2+4i
balandron [24]
The answer it b your welcome
6 0
3 years ago
Read 2 more answers
Anyone knows this?!? ​
IRINA_888 [86]

Answer:

(0.84, 0.88)

Step-by-step explanation:

if you round 0.875 you get 0.88

8 0
2 years ago
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