Answer:
![C=\frac{5F-160}{9}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B5F-160%7D%7B9%7D)
Step-by-step explanation:
Let's solve for C.
![F=\frac{9C}{5}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B9C%7D%7B5%7D)
Step 1: Flip the equation.
![\frac{9}{5} C+32=F](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B5%7D%20C%2B32%3DF)
Step 2: Add
to both sides.
![\frac{9}{5} C+32+-32=F+-32](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B5%7D%20C%2B32%2B-32%3DF%2B-32)
![\frac{9}{5}C=F-32](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B5%7DC%3DF-32)
Step 3: Divide both sides by
.
![\frac{\frac{9}{5}C}{\frac {9} {5}}=\frac{F-32}{\frac{9}{5} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B9%7D%7B5%7DC%7D%7B%5Cfrac%20%7B9%7D%20%7B5%7D%7D%3D%5Cfrac%7BF-32%7D%7B%5Cfrac%7B9%7D%7B5%7D%20%7D)
![C=\frac{5F-160}{9}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B5F-160%7D%7B9%7D)
Answer:
![C=\frac{F-160}{9}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7BF-160%7D%7B9%7D)
Not me
Step-by-step explanation:
Answer:
m<NQS = 32°
Step-by-step explanation:
Given:
m<BQS = 80°
m<BQN = 48°
Required:
m<NQS
SOLUTION:
Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.
Therefore:
m<BQN + m<NQS = m<BQS (angle addition postulate)
48° + m<NQS = 80° (substitution)
m<NQS = 80 - 48° (Subtraction of 48 from each side)
m<NQS = 32°
Answer:
Answer- number D
Step-by-step explanation: