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3 years ago

#13 pls I need this ASAP tmr I my last day!!!

Mathematics

2 answers:

kati45 [8]3 years ago

7 0

Answer:<em> -1 less equals x < 2</em>

aleksandr82 [10.1K]3 years ago

3 0

Answer:

Step-by-step explanation:

-1 is included in the inequality. 2 is not included.

-1 ≤ x < 2

So this reads as x is greater than or equal to - 1 and x is less than 2.

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Ayudemen porfavor . Determine 4 ala potencia x + 4 ala potencia -x, si se sabe que 2ala potencia x + 2 ala potencia -x =3

Afina-wow [57]

Answer:

Es igual a 7.

Step-by-step explanation:

Ok, sabemos que:

$2^x + 2^{-x} = 3$

Queremos calcular:

$4^x + 4^{-x}$

Tambien sabemos que 4 = 2*2

Entonces:

$4^x + 4^{-x} = (2*2)^x + (2*2)^{-x}$

y sabemos que 2*2 = 2^2

Entonces:

$4^x + 4^{-x} = (2*2)^x + (2*2)^{-x} = (2^2)^x + (2^2)^{-x}$

y ahora podemos usar la relación:

$(a^n)^m = (a^m)^n = a^{m*n}$

entonces:

$(2^2)^x + (2^2)^{-x} = (2^x)^2 + (2^{-x})^2$

Ahora podemos completar cuadrados sumando y restando el termino:

$2*(2^x)*(2^{-x})$

Asi tendremos:

$(2^x)^2 + (2^{-x})^2 = (2^x)^2 + (2^{-x})^2 + 2*(2^x)*(2^{-x}) - 2*(2^x)*(2^{-x}) = (2^x + 2^{-x})^2 - 2*(2^x)*(2^{-x})$

Entonces de momento tenemos que:

$4^x + 4^{-x} = (2^x + 2^{-x})^2 - 2*(2^x)*(2^{-x})$

Sabemos que el termino que esta dentro del parentesis es igual a 3.

Y tambien podemos usar la propiedad:

$a^n*a^m = a^{n + m}$

en el termino de la derecha.

Asi tendremos:

$(2^x + 2^{-x})^2 - 2*(2^x)*(2^{-x}) = (3)^2 - 2*2^{x + (-x)} = 9 - 2 = 7$

7 0

3 years ago

Adam rolls a die 96 times. How many times can he expect to roll a 4?

Fed [463]

The answer is B. 96/4

5 0

3 years ago

If a football is thrown upward, its height above the

dybincka [34]

Answer:

a) s = -16 $t^{2}$ + 192t + 96

b) Height of the football after 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

Step-by-step explanation:

Given:

s = -16 $t^{2}$ + $V_{o}$ t + $s_{o}$

where: s is the height of the football above the ground, t is the time, $V_{o}$ is the initial velocity and $s_{o}$ is the initial height.

The height of the building = $V_{o}$ = 192 feet and the initial speed of the ball = $s_{o}$ = 96 feet per second, then;

s = -16 $t^{2}$ + 192t + 96

a) The polynomial is given as:

s = -16 $t^{2}$ + 192t + 96

b) The height of the football when t = 2 seconds is;

s = -16(2) + 192(2) + 96

= -32 + 384 + 96

= -32 + 480

s = 448

The height of the football when t = 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

7 0

3 years ago

What does 74 divided by 8 equal

Darya [45]

8 goes into 74 nine times but there is a remainder of 2

9 and a remainder of 2 or 9 and 1/4

8 0

3 years ago

Read 2 more answers

Differentiate the function with respect to x<br> f(x)= x^4/ x^2- 4<br> Show work

jeyben [28]

Answer:

Step-by-step explanation:

$f(x)=\frac{u}{v} ,u~ and~ v~ functions~ of~ x\\f'(x)=\frac{v ~u'-u~v' }{v^2} \\f(x)=\frac{x^4}{x^2-4} \\f'(x)=\frac{(x^2-4)*4x^3-x^4(2x)}{(x^2-4)^2} \\=\frac{2x^3(2x^2-8-x^2) }{(x^2-4)^2} \\=\frac{2x^3(x^2-8)}{(x^2-4)^2}$

7 0

3 years ago