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Sergio039 [100]
3 years ago
5

an plumber charges a flat rate of $25 for a job and $15 for each hour that he works on the job.how many hours did the plumber wo

rk on a job if the total charge was $85
Mathematics
1 answer:
Illusion [34]3 years ago
4 0

Answer: 3 hours

Step-by-step explanation:

If you add up 25+15=40 if you add up 40+15=55, 55+15=70, 70+15=85

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95 points <br><br> Simplify (4^9/4^3)^5 Show your work for full credit
dexar [7]

Answer:

  • 4^{30}

Step-by-step explanation:

  • (4^9/4^3)^5=
  • (4^{9-3})^5=
  • (4^6)^5=
  • 4^{6*5}=
  • 4^{30}
3 0
2 years ago
Read 2 more answers
Help me please please I beg
alexdok [17]

Answer:

cm

Step-by-step explanation:

if using centimeters to determine the perimeter then it's just cm.

If you're using centimeters to determine area it would be cm^2.

If you're using centimeters to determine volume it would be cm^3.

I hope this helps you. Have a blessed day.

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7 0
2 years ago
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Answer:

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Step-by-step explanation:

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8 0
2 years ago
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3) Last year Kerry’s take home pay was £15 000 She spent 40% of her take home pay on rent. She used the rest of her take home pa
gregori [183]
3,000. You take 15,000 and multiply by .4 to get how much she spent on rent (6,000). They you subtract the rent money from her total pay to get her money that she spent on living expenses, clothes and entertainment in total (9,000). Since she spent her money in six parts (3+2+1), you divide 9,000 by 6 to get 1,500 to get each part. Since for entertainment she has two parts you multiply 1,500 by 2 to get 3,000.
4 0
3 years ago
A rectangle has length that is 5 less than 2 times the width. Write an expression for the area of the rectangle.
a_sh-v [17]

We are given a relationship between the sides of a rectangle, that is, the length of one of its sides is 5 less two times its width, and we are asked to find an expression for the area. Let's remember that the area of a rectangle is equal to the product of the length of its side by its width. Let "w" be the length of the rectangle and "L" its lenght, then the area is given by the following formula:

A=Lw

We can use the relationship given in the problem, that is, its length being five less two times its width, that is:

L=5-2w

Replacing in the formula for the area we get:

A=(5-2w)w

Now we use the distributive law:

A=5w-2w^2

7 0
1 year ago
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