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nataly862011 [7]
3 years ago
11

Which of the following pairs of numbers contains like fractions?

Mathematics
2 answers:
vichka [17]3 years ago
7 0
D because If you multiply the numerator and denominator by 2 you get D
Harrizon [31]3 years ago
4 0

Answer:

D

Step-by-step explanation:

if you multiply 5 by 2 you get 10

if you multiply 6 by 2 you get 12

5/2 (2) =10/12

Hope this helped

:)

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Given the functions f(x) = 2x -1 and g(x) =
Novosadov [1.4K]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

  • f(x) = 2x - 1
  • g(x) =  2 - x

a)

f(x) + g(x) = (2x - 1) + (2 - x)

                = 2x -1 + 2 - x

                = x + 1

b)

f(x) - g(x) = (2x - 1) - (2 - x)

              = 2x - 1 - 2 + x

               = 3x - 3

c)

g(-5) - f(-5)

Putting x = -5 in g(x) = 2 - x

g(x) = 2 - x

g(-5) = 2 - (-5) = 2+5 = 7

Putting x = -5 in f(x) = 2x - 1

f(x) = 2x - 1

f(-5) = 2(-5) - 1

       = -10 - 1

        = -11

Thus,

g(-5) - f(-5) = 7 - (-11) = 7+11 = 18

d)

f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2

e)

f(g(x)) = f(2-x)

          = 2(2-x)-1

          = 4-2x-1

          = 3-2x

6 0
3 years ago
How do you 92 = 8(f + 2) – 4 ?????
Liono4ka [1.6K]
Based on my calculation i know for sure F
would equal 10
8 0
3 years ago
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Can you help me with this please cause I can't do math!
harina [27]

Answer:

6

Step-by-step explanation:

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4 0
3 years ago
The sequence below represents Marisa’s fine at the library for each day that she has an overdue book:
Georgia [21]
The correct answer for the question that is being presented above is this one: "C. f(n) = 0.15n + 0.35." The equation that represents Marisa’s library fine as a function of a book that is n days overdue is f(n) = 0.15n + 0.35

Here are the following choices:
A. f(n) = 0.15n
<span>B. f(n) = 0.50n
</span><span>C. f(n) = 0.15n + 0.35
</span>D. f(n) = 0.50n + 0.15
4 0
3 years ago
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If you divide my number by "-5 and add -2, the result is -4. What's my number?
zepelin [54]

Answer:

10

Step-by-step explanation:

10/-5 = -2

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6 0
3 years ago
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