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VARVARA [1.3K]
3 years ago
12

Count by fives from 135 to 175 write these numbers and describe the pattern

Mathematics
2 answers:
Maru [420]3 years ago
4 0
135 140 140 150 155 160 165 170 175
in this pattern you are adding 5 multiple times
Lera25 [3.4K]3 years ago
3 0

Answer:

The pattern formed is n+5 where n is the previous number in the pattern.

Step-by-step explanation:

Given : Count by fives from 135 to 175.

To find : Write these numbers and describe the pattern ?

Solution :

Count by five means we have to increase the number by 5 each time.

So, We add 5 in each number result,

135 + 5 = 140

140 + 5 = 145

145 + 5 = 150

150 + 5 = 155

155 + 5 = 160

160 + 5 = 165

165 + 5 = 170

170 + 5 = 175

The pattern formed is n+5 where n is the previous number in the pattern.

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Answer: First, draw and label a number line. Then plot the five values that are given above the line. Draw a box from the lower quartile to the upper quartile, with a line dividing it at the median. Then draw lines from the minimum and maximum values connecting to the box to form the whiskers.

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3 years ago
The general solution to the second-order differential equation y′′+10y=0 is in the form y(x)=c1cosβx+c2sinβx. Find the value of
allsm [11]

Answer:β=√10 or 3.16 (rounded to 2 decimal places)

Step-by-step explanation:

To find the value of β :

  • we will differentiate the y(x) equation twice to get a second order differential equation.
  • We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β

y(x)=c1cosβx+c2sinβx

we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.

Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate  βx in each case and multiply with the differential of c1cosx and c2sinx respectively.

lastly the differential of sinx= cosx and for cosx = -sinx.

Knowing all these we can proceed to solving the problem.

y=c1cosβx+c2sinβx

y'= β×c1×-sinβx+β×c2×cosβx  

y'=-c1βsinβx+c2βcosβx

y''=β×-c1β×cosβx + (β×c2β×-sinβx)

y''= -c1β²cosβx -c2β²sinβx

factorize -β²

y''= -β²(c1cosβx +c2sinβx)

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therefore y'' = -β²y

y''+β²y=0

now we compare this with the second order D.E provided in the question

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this means that β²y=10y

β²=10

B=√10  or 3.16(2 d.p)

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3 years ago
Establish for which constants c the following function is a density.
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which means

c=\dfrac3{2^{5/2}}=\dfrac3{4\sqrt2}
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