Answer:Velocity, one of the most frequently used tools for evaluating pitchers, represents the maximum speed of a given pitch at any point from its release to the time it crosses home plate.
Explanation:Velocity, one of the most frequently used tools for evaluating pitchers, represents the maximum speed of a given pitch at any point from its release to the time it crosses home plate.
Answer:
a. CH3COO⁻.
Explanation:
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In this case, according to the given ionization reaction of acetic acid:
CH₃COOH + H₂O --> H₃O⁺ + CH₃COO⁻
Whereas we can evidence how the CH₃COOH is the acid whereas H₂O the base, as the former donates H ions to the latter, which accepts them; we can infer that H₃O⁺ is the conjugate acid, resulting from the base and the a. CH3COO⁻ is the conjugate base, resulting from the acid.
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when the half-life is the amount of time which the radioactive isotopes need to
be in half.
So when w start with 32 g of unobtanium 53 so :
1- after 20 sec the number of grams remain = 32/2
= 16 g
2- and after 40 sec the number of grams remain
16 g will cut in half:
= 16 / 2
= 8 g
3- and after 60 sec the number of grams remain
8 g will cut in half:
= 8g /2
= 4 g
4- and after 80 sec the number of grams remain
4 g will cut in half:
= 4 g /2
= 2 g
5-after 100 sec the number of grams remain
2 g will cut in half :
= 2g /2
= 0 g
after 100 sec there are no grams remain
Answer:
their warfare had changed dramatically
Explanation:
The chemical reaction equation will be as follows.
As 1 mole 
reacts with 1 mole of 
Hence, moles of = Molarity × Volume (in mL)
= 0.5 × 38.0 mL
= 0.019 mol
Moles of = Molarity × Volume (in mL)
= 0.6 × 42.0 mL
= 0.0252 mol
As moles of CuS is less than the moles of . This means that CuS is the limiting reagent.
Thus, maximum moles of CuS formed are 0.019 mol. As molar mass of CuS is 95.6 g/mol.
Therefore, maximum mass of CuS can be formed is 
= 1.8164 g
Thus, we can conclude that maximum mass of CuS formed is 1.8164 g.
