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zysi [14]
3 years ago
7

Copper(II) sulfide, CuS, is used in the development of aniline black dye in textile printing. What is the maximum mass of CuS wh

ich can be formed when 38.0 mL of 0.500 M CuCl2 are mixed with 42.0 mL of 0.600 M (NH4)2S
Chemistry
1 answer:
IrinaK [193]3 years ago
6 0

Explanation:

The chemical reaction equation will be as follows.

           CuCl_{2} + (NH_{4})_{2}S \rightarrow 2NH_{4}Cl + CuS

As 1 mole CuCl_{2} reacts with 1 mole of (NH_{4})_{2}S

Hence, moles of CuCl_{2} = Molarity × Volume (in mL)

                                              = 0.5 × 38.0 mL

                                              = 0.019 mol

Moles of (NH_{4})_{2}S = Molarity × Volume (in mL)

                                           = 0.6 × 42.0 mL

                                           = 0.0252 mol

As moles of CuS is less than the moles of (NH_{4})_{2}S. This means that CuS is the limiting reagent.

Thus, maximum moles of CuS formed are 0.019 mol. As molar mass of CuS is 95.6 g/mol.

Therefore, maximum mass of CuS can be formed is 95.6 g/mol \times 0.019 mol

                    = 1.8164 g

Thus, we can conclude that maximum mass of CuS formed is 1.8164 g.

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alex41 [277]
Original molarity was 1.7 moles of NaCl

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Given Information:

Original (concentrated) solution: 25 g NaCl in a 250 mL solution, solve for molarity

Final (diluted) solution: More water is added to make the new total volume 1.2 liters, solve for the new molarity

1. Solve for the molarity of the original (concentrated) solution.

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Molarity (M) = 0.43 mol NaCl solute / 0.250 L solution = 1.7 M NaCl (original solution)

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