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Lemur [1.5K]
3 years ago
11

Identify the conjugate base in the equation below

Chemistry
1 answer:
givi [52]3 years ago
5 0

Answer:

a. CH3COO⁻.

Explanation:

Hello there!

In this case, according to the given ionization reaction of acetic acid:

CH₃COOH + H₂O --> H₃O⁺ + CH₃COO⁻

Whereas we can evidence how the CH₃COOH is the acid whereas H₂O the base, as the former donates H ions to the latter, which accepts them; we can infer that H₃O⁺ is the conjugate acid, resulting from the base and the a. CH3COO⁻ is the conjugate base, resulting from the acid.

Best regards!

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The pH of a solution of a is increased from 2 to 3 then the concentration of h + ions will become​
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The H+ concentration would decrease by 10 fold. From .01 to .001

Explanation:

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Write the conversion factor(s) for<br> (a) cm/min to in/s<br> (b) m3 to in3<br> (C) m/s2 to km/h2
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Answer :

(a) 1cm/min=6.56\times 10^{-3}in/s

(b) 1m^3=61023.7in^3

(c) 1m/s^2=7.716\times 10^{-11}km/hr^2

Explanation:

(a) cm/min to in/s

The conversion factor used :

1cm=\frac{1}{2.54}in

and,

1min=60s

So, \frac{1cm}{1min}\times \frac{1in}{2.54cm}\times \frac{1min}{60s}

\Rightarrow 6.56\times 10^{-3}in/s

Thus, 1cm/min=6.56\times 10^{-3}in/s

(b) m^3\text{ to }in^3

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1m^3=61023.7in^3

Thus, 1m^3=61023.7in^3

(c) m/s^2\text{ to }km/hr^2

The conversion factor used :

1m=\frac{1}{1000}km

and,

1s=\frac{1}{3600}hr

So, \frac{1m}{1s^2}\times \frac{1km}{1000m}\times \frac{1s^2}{3600\times 3600hr^2}

\Rightarrow 7.716\times 10^{-11}km/hr^2

Thus, 1m/s^2=7.716\times 10^{-11}km/hr^2

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