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Naya [18.7K]
3 years ago
11

Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y

2 Is the student’s work correct? No, she did not multiply –6y2 by 2 correctly. No, she did not add 3y2 and –12y2 correctly. No, she did not use the distributive property correctly. Yes, she multiplied the binomials correctly.
Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0

Answer:

No, She did not use the distributive property correctly.

Step-by-step explanation:

While multiplying (3-6y^2)(y^2+2), he did not use distributive property correctly. She only multiplied 3 with y^2 and not with 2. Also she multiplied -6y^2only with 2 and not with y^2.

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the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width
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<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.  

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

Hence length and width of rectangle is 15 inches and 6 inches.

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