Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y

Question

2 years ago

11

Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y

2 Is the student’s work correct? No, she did not multiply –6y2 by 2 correctly. No, she did not add 3y2 and –12y2 correctly. No, she did not use the distributive property correctly. Yes, she multiplied the binomials correctly.

Mathematics

1 answer:

vladimir2022 [97] · Answer 1 · 2022-08-28T00:23:49+03:00

vladimir2022 [97]2 years ago

6 0

Answer:

No, She did not use the distributive property correctly.

Step-by-step explanation:

While multiplying $(3-6y^2)(y^2+2)$ , he did not use distributive property correctly. She only multiplied 3 with $y^2$ and not with 2. Also she multiplied $-6y^2$ only with 2 and not with $y^2$ .