Given the total number of students are 180, the mean of data is 88g, and standard deviation is 1g.
A normal curve is a bell-shaped curve with symmetry about the mean and it spreads uniformly on both sides (left side and right side) of the mean.
The empirical rule is also called "68-95-99.7" rule. It says that :-
A) 68% of the data values fall between 1 standard deviation about mean (34% on left side and 34% on right side),
B) 95% of the data values fall between 2 standard deviations about mean (47.5% on left side and 47.5% on right side), and
C) 99.7% of the data values fall between 3 standard deviations about mean (49.85% on left side and 49.85% on right side).
According to distribution of normal curve and "68-95-99.7" empirical rule, we can say 49.85% of data values are above the mean within 3 standard deviations.
So it means 49.85% of total students report readings more than 88g.
Number of students reporting readings more than 88g = 49.85% of 180 = 0.4985 × 180 = 89.73
Hence, approximately 89 students report readings more than mean value.
Step-by-step explanation:
Hey there!
The equation of a st.line passing through points (4,5) and (7,3) is;

<u>Put</u><u> </u><u>all values</u><u>. </u>
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<u>Simplify</u><u> </u><u>it</u><u>. </u>
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<u>Therefore the</u><u>required</u><u> </u><u>equation</u><u> </u><u>is</u><u> </u><u>2</u><u>x</u><u>+</u><u>3</u><u>y-23</u><u>=</u><u>0</u><u>.</u>
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
Using trigonometric identities, it is found that the sine and the tangent of the angle are given as follows:
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<h3>How do we find the sine of an angle given the cosine?</h3>
We use the following identity:

In this problem, the cosine is:

Hence the sine is found as follows:




Second quadrant, so the sine is positive, hence:

<h3>What is the tangent of an angle?</h3>
The tangent is given by the <u>sine divided by the cosine</u>, hence:

Hence:



More can be learned about trigonometric identities at brainly.com/question/7331447
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Answer:
<h2>50, percentage decreased by 14% (percent) of its value = 43</h2>