According to the direct inspection, we conclude that the best approximation of the two solutions to the system of <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)
<h3>What is the solution of a nonlinear system formed by two quadratic equations?</h3>
Herein we have two parabolae, that is, polynomials of the form a · x² + b · x + c, that pass through each other twice according to the image attached to this question. We need to estimate the location of the points by visual inspection on the <em>Cartesian</em> plane.
According to the direct inspection, we conclude that the best approximation of the two solutions, that is, the point where the two parabolae intercepts each other, to the system of two <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)
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Answer:
To multiply decimals, first multiply as if there is no decimal. Next, count the number of digits after the decimal in each factor. Finally, put the same number of digits behind the decimal in the product.
Answer:
The ordered pair (-6, -1) is the only solution.
Step-by-step explanation:
-6x + y = 35
Let's plug in the points.
(-1, -7) --> -6(-1) - 7 = 6 - 7 = -1 which does not equal 35
(-6, -1) --> -6(-6) -1 = 35
(-1, -6) --> -6(-1) - 6 = 0 which does not equal 35
(-7, -1) --> -6(-7) - 1 = 41 which does not equal 35
Answer:
f(x)=-x2
Step-by-step explanation:
I believe the first one has a vertex at (-4, 0), the second at (4, 0), the third at (4, -4). The only remaining answer is the last one.
