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oksano4ka [1.4K]
3 years ago
14

Arthur earned $22.50 last night delivering lunches for his family's restaurant. He puts 30% of his earnings into his savings acc

ount. he then bought a magazine for $3.95 and a CD for $11.49. of the amount earned last night, how much money does arthur have left that is not in his savings account​
Mathematics
1 answer:
ira [324]3 years ago
6 0

Answer:

$4.26

Step-by-step explanation:

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How to add the rational expression d^2/d-2+3/2x+4
Elden [556K]

\frac{d^2}{d} - 2 + \frac{3}{2}x + 4\\= d + \frac{3}{2} x + 2

7 0
3 years ago
Which is greater 6 kilometets or 600 cm
Luba_88 [7]

Answer:

6km>600cm

Step-by-step explanation:

to compare we can bring to the same unit

we can convert to meters

600cm=6m

6km=6000m

6000m>6m

6km>600cm

8 0
3 years ago
Read 2 more answers
Find the length of the third side. If necessary, write in simplest radical form.
8090 [49]

Answer:

The missing side is 8 ( with radical form )

64 without doing radical

Step-by-step explanation:

Hope this helps

6 0
3 years ago
In a tank of water, a can of regular soda will sink to the bottom, but a can of diet soda will float.
Svetach [21]
Over 140 times bigger because 25 cm³ of sugar is 40 grams (25×1.6)
and .2 cm³ of aspartame is 0.27 grams (0.2×1.35)
and 40 is 148 times as big as 0.27 (0.27×148.1481481≈40)
8 0
3 years ago
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Find two consecutive odd integers such that the square of the first added to 3 times the second, is 24. Part a: Define the varia
fgiga [73]

Given:

There are two consecutive odd integers such that the square of the first added to 3 times the second, is 24.

To find:

Part a: Define the variables.

Part b: Set up an equations that can be solved to find the integers.

Part c: Find the integers.

Solution:

Part a:

Let x be the first odd integers. Then next consecutive odd integer is x+2, because the difference between two consecutive odd integers is 2.

Part b:

Square of first odd integers = x^2

Three times of second odd integers = 3(x+2)

It is given that the sum of square of first odd integers and three times of second odd integers is 24. So, the required equation is:

x^2+3(x+2)=24

Part c:

The equation is:

x^2+3(x+2)=24

It can be written as:

x^2+3x+6=24

x^2+3x+6-24=0

x^2+3x-18=0

Splitting the middle term, we get

x^2+6x-3x-18=0

x(x+6)-3(x+6)=0

(x-3)(x+6)=0

x=3,-6

-6 is not an odd integer, so x=3 and the first odd integer is 3.

Second odd integer = x+2

                                  = 3+2

                                  = 5

Therefore, the two consecutive odd integers are 3 and 5.

8 0
3 years ago
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