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3 years ago

How to write a slope intercept equation from a graph?

Mathematics

1 answer:

saul85 [17]3 years ago

5 0

The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

y = -1/2x + 5 is the answer

M = Rise over run meaning you go up 1 and run the other way (left or right) 2

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What is the simplified form of the following expression? 2√27+√12-3√3-2√12

LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$

but

$2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}$

$\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}$

Since √12=2√3,this implies that,

$2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}$

Therefore,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}$

$=(6+2-3-4)\sqrt{3}$

$=\sqrt{3}$

The simplified form of ,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$ is √3

8 0

3 years ago

Point N is on line segment MO. Given MN = x, MO = 3x - 6,

finlep [7]

Answer:

Step-by-step explanation:

N is between points M and O

MN = x

MO = 3x - 6

NO = x + 1

The way it reads MN + NO = MO

x + x + 1 = 3x - 6

2x + 1 = 3x - 6

2x - 2x +1 = 3x -2x - 6

1 = x - 6

1 + 6 = x

x = 7

MO = 3x - 6

MO = 3*7 - 6

MO = 21 - 6

MO = 15

7 0

3 years ago

The following chart shows the number of concert tickets sold and the profit earned. What is the slope of the line through these

Black_prince [1.1K]

Answer:

C.) 4

Step-by-step explanation:

y2 - y1/x2 - x1

m = 160 - 80/60 - 40

m = 80/20

m = 8/2

m = 4/1

m = 4

8 0

2 years ago

Solve for x by factoring. Check your answers. Can you check to see if I'm correct?

Studentka2010 [4]

If you want to check if your answer is correct, expanding it all out will help!

(x-6)(x+2)=0 <-- Use FOIL tactic

x²+2x-6x-12=0

x²-4x-12=0

As you can see, this is identical to the initial equation given. The x values would be 6 and -2, as seen from the factored equation.

Hope I helped :)

7 0

3 years ago

Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.

Masja [62]

Answer:

See below.

Step-by-step explanation:

So, we have:

$\sec(\theta)=-2/\sqrt{3}$

Recall that secant is simply the reciprocal of cosine. So we can:

$\cos(\theta)=(\sec(\theta))^{-1}=(-2/\sqrt{3})^{-1}\\\cos(\theta)=-\sqrt{3}/2$

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.

Therefore, the possible values for theta is

5π/6 +2nπ

and

7π/6 + 2nπ

6 0

3 years ago