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bulgar [2K]
3 years ago
5

Need help with numbers 8 and 9

Mathematics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

did not understand ur q.a

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Solve the following equation: 3x^3+5x^2-4x-4=0
Rama09 [41]

Answer:

1

Step-by-step explanation:

Simplifying

3x + 2(4x + -4) = 3

Reorder the terms:

3x + 2(-4 + 4x) = 3

3x + (-4 * 2 + 4x * 2) = 3

3x + (-8 + 8x) = 3

Reorder the terms:

-8 + 3x + 8x = 3

Combine like terms: 3x + 8x = 11x

-8 + 11x = 3

Solving

-8 + 11x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.

-8 + 8 + 11x = 3 + 8

Combine like terms: -8 + 8 = 0

0 + 11x = 3 + 8

11x = 3 + 8

Combine like terms: 3 + 8 = 11

11x = 11

Divide each side by '11'.

x = 1

Simplifying

x = 1

5 0
3 years ago
20 points!!! Please Help<br><br> Does the equation x2 - 4x + y2 = -3 intersect the x-axis?
OverLord2011 [107]

Answer:

Yes, twice

Step-by-step explanation:

The equation will intersect the x-axis when y = 0, so we have

x² - 4x = -3    now solve this quadratic for x...

  x² - 4x + 3 = 0    

factor...

(x - 3)(x - 1) = 0,

so at x = 1 and x = 3, the function crosses the x-axis

See the graph below

6 0
3 years ago
Read 2 more answers
(5+6b^3)^2 expand and combine like terms
Drupady [299]

Answer:

( 5 + 6b^3)^2 = 36b^6 + 60b^3 + 25

Step-by-step explanation:

(a + b)^2 = a^2 + b^2 + 2ab

So,

        (5 + 6b^3)^2 = (5)^2 + (6b^3)^2 + 2 (5)(6b^3)

                       = 25 + 36b^6 + 60b^3

7 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
Elodia [21]

Answer:

Hope this helps, happy learning!!!

3 0
3 years ago
Angle C is an inscribed angle of circle P. Angle C measures (x + 5)° and arc AB measures (4x)° . Find x.
erastova [34]

Step-by-step explanation:

m \angle \: C =  \frac{1}{2} (m \: arc \: AB)\\(By\:inscribed \:\angle\:theorem) \\  \\  \therefore \: (x + 5) \degree =\frac{1}{2} (4x)\degree  \\  \\ \therefore \: x + 5=\frac{1}{2} \times  4x \\  \\ \therefore \: x + 5=2x \\  \\ \therefore \: x  - 2x =  - 5 \\  \\ \therefore \:  - x =  - 5 \\  \\ \:  \:  \:  \:  \:   \huge \purple{ \boxed{\therefore \:  x =   5}}

6 0
3 years ago
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