1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.
f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]
21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]
2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.
j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]
17 + 7j = 87
3.) n = number of calls
18 + 0.05n = 50.50
[Company charges $18 plus five cents per call(n), and the total charge was $50.50]
4.) s = the number of students
40 + 30s = 220
[Tutor charges $40 plus $30 per student(s), and the total charge was $220]
Answer:
15.25
Step-by-step explanation:
We can use a factorial to solve this:
3! = 3 * 2 * 1 = 6
So, she can wear them in a total of 6 combos.
Answer:
y = x² - 2x - 3
Step-by-step explanation:
y + 4 = C(x - 1)²
To determine C, use x = 4, y = 5
5 + 4 = C(4 - 1)²
9 = 9C, C = 1
y + 4 = (x - 1)² = x² - 2x + 1
y = x² - 2x - 3
1. Take away the parentheses. x+2x+40+3x-50=15002
2. Add the X’s together.
x+2x+3x= 6x —> 6x+40-50=15002
3. Subtract 50 from 40.
40-50= -10 —> 6x-10=15002
4. Move -10 to the right hand side to make it positive.
6x=15002+10
5. Add 15002 and 10 together.
6x=15012
6. Divide 15012 by 6. Which makes the answer X=2502