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3 years ago

Express the decimal: 0.60 as a fraction

Mathematics

2 answers:

Nezavi [6.7K]3 years ago

5 0

Answer:

3/5

Step-by-step explanation:

Delicious77 [7]3 years ago

3 0

Answer:

$\frac{60}{100}$

or more simplified:

$\frac{6}{10}$

or more-more simplified:

$\frac{3}{5}$

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Write 1.50 as a mixed number

GaryK [48]

The answer is 150 over 100 hope this helps

4 0

3 years ago

The day's high temperature in St. Louis comma Missouri was recorded as 77 degrees' F. Use the formula Upper C=5/9(F-32) to writ

ludmilkaskok [199]

Answer:

The day's high temperature written as degrees Celsius is 25 degrees' Celsius.

Step-by-step explanation:

The day's high temperature in St. Louis ,Missouri was recorded as 77 degrees F.

We are supposed to find the day's high temperature written as degrees Celsius.

Formula : $C=\frac{5}{9}(F-32)$

Substitute the value of F is 77 degrees

So, $C=\frac{5}{9}(77-32)$

$C=\frac{5}{9}(45)$

C=25

Thus, The day's high temperature written as degrees Celsius is 25 degrees' Celsius.

6 0

3 years ago

Somebody please help me

Mazyrski [523]

Plan A: 30 + 0.01m
Plan B: 20 + 0.05m
in order for 2 plans cost the same, both need to be equal
so should be

20 + 0.05m = 30 + 0.01m

answer is D. last one
20 + 0.05m = 30 + 0.01m

8 0

3 years ago

Write a mathematical sentence that expresses the information given below. Use t as your variable name. If necessary:Susanne chec

Feliz [49]

Answer:

$t+8>82^{\circ}$

Explanation:

We were given that:

Let "temperature" be represented by "t"

Suzan checks the temperature at 11:00. If the temperature rises by 8 more degrees, it will break the record high temperature for the day which is 82 degrees

This information is mathematically represented as:

$t+8>82^{\circ}$

7 0

1 year ago

PLEASE HELP! Find the distance between each pair of points. Round your answers to the nearest tenth.

strojnjashka [21]

A.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \left( -5 \right) \right)^2 + \left( -2 - \left( -3 \right) \right)^2} \\ \\ = \sqrt{ 1 + 1} \\ \\ = \sqrt{ 2 }$

b.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \frac{ 7 }{ 2 } \right)^2 + \left( \frac{ 5 }{ 2 } - 1 \right)^2} \\ \\= \sqrt{ \frac{ 225 }{ 4 } + \frac{ 9 }{ 4 }} \\ \\= 3 \frac{\sqrt{ 26 }}{ 2 }$

6 0

3 years ago