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pickupchik [31]
3 years ago
9

Complete the steps to demonstrate why you multiply by the reciprocal when dividing fractions

Mathematics
1 answer:
choli [55]3 years ago
5 0
1/2 ÷ 1/2
= 1/2 ÷ 2/1
= 1/2 × 2/1
= 2/2
= 1
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Joshua made note of all the bicycles and cars he could see parked or locked on a
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Answer:

56

Step-by-step explanation:

11*4=44

6*2=12

44+12=56

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Box of cereal contains 23.4 ounces. Cost $5.49. What’s the cost per ounce?
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it 4.262295082

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you have to divid the ounces by the cost

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3 years ago
Pleaaasee need correct answer! Brainliest(:
larisa86 [58]

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Choice 4 is the correct answer

7 0
2 years ago
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Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Please help me! I REALLLY need my math grade to go up!!! PLEASE HELP!!!!
melomori [17]

Answer:

Hi I only know part be yes the figures are congruent

Step-by-step explanation:

There the same shape, same size so yes they are congruent

6 0
2 years ago
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