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xeze [42]
3 years ago
5

Write X^-2y^0z^2/xy using only positive exponents

Mathematics
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

  z^2/(x^3y)

Step-by-step explanation:

We assume you want to simplify ...

  \dfrac{x^{-2}y^0z^2}{xy}=x^{-2-1}y^{0-1}z^2=x^{-3}y^{-1}z^2\\\\=\boxed{\dfrac{z^2}{x^3y}}

_____

<em>Comment on the given expression</em>

What you have written is ...

  (x^-2y^0z^2/x)y = yz^2/x^3

The order of operations requires that division and multiplication be done in the order of appearance, so a/xy means (a/x)y unless you put parentheses on the denominator product. Typesetting the expression lets you use the fraction bar for grouping, so parentheses are not needed when that form is used.

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Answer:

A = $44,778.84

A = P + I where

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Given: Yvonne bought a car for $10,300. After 3 years, the value of the car was $6,250. 50%

To find: In approximately what number of additional months will the value of Yvonne’s car be 50% of the price she originally paid?

Formula: (\frac{interest rate}{number of payments}) × loan principal = interest

Solution:  Divide your interest rate by the number of payments you’ll make in the year (interest rates are expressed annually). So, for example, if you’re making monthly payments, divide by 12. Multiply it by the balance of your loan, which for the first payment, will be your whole principal amount.

(This gives you the amount of interest you pay the first month.)

First, convert R as a percent to r as a decimal

r = R/100

r = 50/100

r = 0.5 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

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A = 10,300.00(1 + 0.041666667)(36)

A = $44,778.84

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The total amount accrued, principal plus interest, with compound interest on a principal of $10,300.00 at a rate of 50% per year compounded 12 times per year over 3 years is $44,778.84.

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