Answer:
144°
Step-by-step explanation:
step 1
Find the measure of the central angle of the regular pentagon
Divide 360 degrees by 5 (the number of sides)
Let
c----> the center of the pentagon
we know that
m∠ECA=72°
m∠ACB=72°
therefore
m∠ECB=m∠ECA+m∠ACB
substitute the values
m∠ECB=72°+72°=144°
The measure of angle ECB is equal to the degrees that the pentagon rotate
Answer:
The height of the equilateral triangle is 24 units
Step-by-step explanation:
In the question above, the unit of the side of the equilateral triangle is not given. If the complete question is:
Triangle MNO is an equilateral triangle with sides measuring 16 square root of 3 units, then the length of each side is 16√3 units.
To find the height of the triangle, we use Pythagoras theorem
MP^2 + PO^2 = MO^2
Let MP^2 be x
x^2 + {(16√3)/2}^2 = (16√3)^2
X^2 + (256*3)/4 = 256*3
4x^2 + 768 = 768* 4
4x^2 + 768 = 3072
4x^2 = 3072-768
4x^2 = 2304
X^2 = 2304/4
X^2 = 576
x= √576
x = 24 units
