3 years ago

Train a has a speed 15 miles per hour greater than that of train

Mathematics

1 answer:

Sonbull [250]3 years ago

6 0

Train a speed = x+15

Train b speed =x

255/x = 300/(x+15)

255(x+15) = 300x

255x +3825 =300x

3825 = 45x

X = 3825/45 =85

<span>Train B = 85 miles per hour</span>

<span> Train A = 85+15 = 100 miles per hour</span>

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