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3 years ago

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katy miedzy ramionami trojkata rownoramiennego jest rowny 130 stopni . oblicz miary pozostalych katow wewnetrznych w tym trojkac

ie

1 answer:

kotegsom [21]3 years ago

5 0

What is your question

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How do you solve f(x) = 800(1.09)3x

natta225 [31]

Answer:

2616x

Step-by-step explanation:

8 0

3 years ago

I have 7 mins to turn in, what’s the answer?? thanks :)

Ostrovityanka [42]

Answer:

A) x = 10-/3, y = 20

Step-by-step explanation:

8 0

3 years ago

Which list represents the independent values on this graph? 0, 100, 250, 200, 300, 350, 400, 500, 650, 700, 750 1, 2, 3, 4, 5, 6

worty [1.4K]

A scatter plot is used to relate the dependent and the independent values

The list of independent values is:1, 2,3, 4,5,6,7,8,9,10

<h3>How to determine the independent values</h3>

The ordered pairs on the scatter plot are:

(x,y) = (1, 100), (2,250) , (3,200) , (4,300), (5,400), (6,350), (7,500) , (8,650) , (9,700) and (10,750).

Remove the y values

x = 1, 2,3, 4,5,6,7,8,9,10

The x values represent the independent values

Hence, the list of independent values is:1, 2,3, 4,5,6,7,8,9,10

Read more about scatter plots at:

brainly.com/question/6592115

8 0

2 years ago

An arithmetic sequence is represented in the following table. Enter the missing term of the sequence.

Allisa [31]

Answer:

329.5

Step-by-step explanation:

From the table we see that the common difference d = 0.5 - (-6.5)

= 7, and 7.5 - 0.5 = 7. Also 14.5 - 7.5 = 7.

The first term a1 = -6.5.

The nth term = a1 + (n - 1)d so for our sequence we have:

49th term = -6.5 + (49 - 1)7

= -6.5 + 48 * 7

= -6.5 + 336

= 329.5 (answer).

4 0

3 years ago

the vertex of this parabola is at (3,5). When the y-value is 6, the x-value is -1. What is the coefficient of the squared term i

otez555 [7]

Now, assuming is a vertical parabola, so the squared variable is the "x", let's do some checking.

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=3\\
k=5
\end{cases}\implies y=a(x-3)^2+5
\\\\\\
\textit{we also know that }
\begin{cases}
y=6\\
x=-1
\end{cases}\implies 6=a(-1-3)^2+5
\\\\\\
1=a(-4)^2\implies 1=16a\implies \cfrac{1}{16}=a$

6 0

3 years ago