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irga5000 [103]
3 years ago
8

14. Enzo needs to buy some sand for his sandbox. He can either buy a

Mathematics
1 answer:
timama [110]3 years ago
8 0

Answer:

A: 6 kilo bag B: He should buy two 10 pound bags.

Step-by-step explanation:

Brainliest?

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Write a unit for the situation. $12.50 for 5 ounces
Goshia [24]

Answer:

$2.50 per ounce

Step-by-step explanation:

12.5/5=2.5

6 0
3 years ago
NEED HELP ASAP WILL GIVE BRAINLYEST IF CORRECT Which model shows two equal expressions when a = 4?
Elan Coil [88]
The correct answer would be D.
3 0
3 years ago
Read 2 more answers
10. 14. A new DVD player has a purchase price of $430. With the extended warranty, the total cost is
sergejj [24]
Subtract 430 and 512 and turn into a percent
82%
Than 430+512is942
Divide by 82%is11.487804
Skip a few times until u reach 11.48
Add 4+8 and then dvd:1 dvd to buy
So 4+8is12 plus 11 is 23 and one dvd it’s 24
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5 0
3 years ago
Happy Friday!! :) I need help with this question.
Vedmedyk [2.9K]

Answer:

3

Step-by-step explanation:

Terms are the values in an expression. They include exponents and variables. in this expression there are three terms:

1 - 5x

2 - 2y

3 - 12

4 0
3 years ago
An economist wondered if people who go grocery shopping on weekdays go more or less often on Fridays than any other day. She fig
Kamila [148]

Answer:

There is not enough statistical evidence to state that the true proportion of grocery shoppers from Monday to Friday that goes most frequently on Fridays is different from 20%. The p - value is 0.0130.

Step-by-step explanation:

To solve this problem, we run a hypothesis test about the population proportion.

Proportion in the null hypothesis (p0) = 0.2

Sample size (n) = 75

Sample proportion (sp) = 24/75 = 0.32

Significance level = 0.01

H0: p = 0.2

Ha: p \neq 0.2

Test statistic = (sp - p0) / sqrt ((p0) (1-p0) / n)

Left critical Z value (for 0.01) = -2.5758

Right critical Z value (for 0.01) = 2.5758

Calculated statistic = (0.32 - 0.2) / sqrt ((0.32) (1-0.32) / 75) = 2.2278

Since, -2.5758 < Test statistic < 2.5758, the null hypothesis cannot be rejected. There is not enough statistical evidence to state that the true proportion of grocery shoppers from Monday to Friday that goes most frequently on Fridays is different from 20%. The p - value is 0.0130.

5 0
3 years ago
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