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zubka84 [21]
3 years ago
10

A set of Numbers is shown below.

Mathematics
1 answer:
8090 [49]3 years ago
4 0

Answer: A

Step-by-step explanation:

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20×^2-30x-40 solve for x
Oduvanchick [21]

Answer:

x = 12

Step-by-step explanation:

Solve for x:

360 - 30 x = 0

Subtract 360 from both sides:

(360 - 360) - 30 x = -360

360 - 360 = 0:

-30 x = -360

Divide both sides of -30 x = -360 by -30:

(-30 x)/(-30) = (-360)/(-30)

(-30)/(-30) = 1:

x = (-360)/(-30)

The gcd of 360 and -30 is 30, so (-360)/(-30) = (-(30×12))/(30 (-1)) = 30/30×(-12)/(-1) = (-12)/(-1):

x = (-12)/(-1)

(-12)/(-1) = (-1)/(-1)×12 = 12:

Answer:  x = 12

4 0
3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
Simplify h + h + h , I really need help
lyudmila [28]
3h

Explanation:

Add them
4 0
3 years ago
Read 2 more answers
HELP I DONT GET #10! PLZ HELP!
zhenek [66]
Yes, there will be more than 100 inches because there are 12 inches in a foot so it’s 100x12 which means it’s going to be 1,200 inches per second
8 0
3 years ago
Need help on this one
Lady_Fox [76]
To find what y is you have to do y1-y2/x1 - x2



Hope this helped
3 0
3 years ago
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